我做下一个查询:
select case when anum like '0%' then 0 else 1 end anum ,
,voucher
, date
from ledger
group by voucher, date, case when accountnum like '0%' then 0 else 1 end
order by voucher
之后我需要在一个查询中计算anum。
答案在这里: 我查询上面写的内容。然后我得到以下结果:
anum voucher date
1 1 2012-09-30
29 1 2012-09-30
2 101 2012-11-01
2 1131_3 2012-01-01
4 1131_11 2012-05-22
4 1131_11 2012-05-22
但我想看到这个:
anum voucher transdate
2 1 2012-09-30
1 101 2012-11-01
1 1131_3 2012-01-01
2 1131_11 2012-05-22
答案 0 :(得分:0)
只需将其放在子查询中:
select count(*) as anum, voucher, date
from (
select case when anum like '0%' then 0 else 1 end anum ,
,voucher
, date
from ledger
group by voucher, date, case when accountnum like '0%' then 0 else 1 end
order by voucher
) sq
group by voucher, date