Question

当我在SalasController debug($this->data)方法上reservar()时，来自json的$ data是可以的，但当我this->Sala->save($this->data)时，debug($data)上的beforeSave()返回：

Notice (8): Undefined property: FormataDataBehavior::$data [APP\Model\Behavior\FormataDataBehavior.php, line 52]
\app\Model\Behavior\FormataDataBehavior.php (line 52)
null

SalasController.php

App::uses('AppController', 'Controller');

class SalasController extends AppController {

public $components = array('RequestHandler');

public function beforeFilter() {
    parent::beforeFilter();
    $this->Auth->allow('listar', 'reservar');
    $this->RequestHandler->addInputType('json', array('json_decode', true));
}
    public function reservar() {
    $this->Sala->save($this->data); //no conditions just for debugging.
}

模型Sala.php

class Sala extends AppModel {

public $useTable = 'agenda';
public $actsAs = array(
    'FormataData' => array('dia')
);

行为

class FormataDataBehavior extends ModelBehavior {

// Armazena os campos do model a serem formatados.
public $campos;

//Inicializa o behavior
public function setup(Model $model, $settings = array()) {
    if (!empty($settings)) {
        $this->campos[$model->name] = $settings;
    } else {
        throw new MethodNotAllowedException('Campos data não informados na declaração do behavior');
    }
}

public function beforeSave(Model $model, $options = array()) {
    parent::beforeSave($model, $options);
    debug($this->data); //trying show data, but is !isset... =/
    die();
}

MyJs

function adicionarReserva() {
var dadosForm = {Sala: {}};
$.each($("#form-reservas").serializeArray(), function(index, value) {
    dadosForm.Sala[value.name] = value.value;
});
$.post("/intracake/Salas/reservar.json", dadosForm)
        .done(function(data) {
            sysMsg(data.html);
            atualizaTabelas();
        });
}

Answer 1

我之前在@Holt提示之后保存;

public function beforeSave(Model $model, $options = array()) {
    parent::beforeSave($model, $options);
    $this->formataBeforeSave($model);
    return true;
}

public function formataBeforeSave(Model &$model, $padrao = 'Y-m-d') {
    foreach ($this->campos[$model->name] as $campo) {
        if (isset($model->data[$model->name][$campo]) && !empty($model->data[$model->name][$campo])) {
            $model->data[$model->name][$campo] = $this->converte($model, $model->data[$model->name][$campo], $padrao);
        }
    }
}

Cakephp的beforeSave（）没有使用$ model :: save（）保留新数据

1 个答案: