Question

我想使用webservice来点击我的按钮后获取数据（button1）不幸地停止了我正在使用json我的调试器没有来onclick视图而我的json没有给出响应。

JSONParser jsonParser = new JSONParser();
private static final String about = "about"; 
private static String url = "http://www.mydomain/staticinfo";
private static final String TAG_SUCCESS = "id"; 
private static final String TAG_SUCCESS1="success";


@SuppressLint("NewApi")
protected void onCreate(Bundle savedInstanceState) {
    StrictMode.setThreadPolicy(new StrictMode.ThreadPolicy.Builder()
    .detectDiskReads().detectDiskWrites().detectNetwork()
    .penaltyLog().build());
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);
    addListenerOnButton();
}
public void action(View v)
{
    if(v.getId()==R.id.button1)
        new aboutAccess().execute();
    else
        Toast.makeText(this, "This is demo for smlsolution", Toast.LENGTH_LONG).show();
}
class aboutAccess extends AsyncTask<String, String, String>{
    private String id;
    protected void onPreExecute() {
        super.onPreExecute();
        pDialog = new ProgressDialog(MainActivity.this);
        pDialog.setMessage("Wait...");
        pDialog.setIndeterminate(false);
        pDialog.setCancelable(true);
        pDialog.show();
    }

    @Override
    protected String doInBackground(String... arg0) {
         //String url = "http://10.0.2.2/about.php";
        List<NameValuePair> params = new ArrayList<NameValuePair>();
        String ID="1";
        params.add(new BasicNameValuePair("id ","ID"));
        JSONObject json = jsonParser.makeHttpRequest(url,"POST", params);
        Log.d("Create Response", json.toString());
        try{
            int success = json.getInt(TAG_SUCCESS);
            if (success == 1) {
                flag=0; 
                  String abt=json.getString(about);
                  Intent i = new Intent(getApplicationContext(),About.class);
                  i.putExtra("about", abt);
                  startActivity(i);
            }
            else{
                flag=1;
            }
        } 
         catch (JSONException e){
             e.printStackTrace(); 
             System.out.println(e.toString());
         }

        // TODO Auto-generated method stub
        return null;
    }

    protected void onPostExecute(String file_url){
        pDialog.dismiss();
        if(flag==1)
            Toast.makeText(MainActivity.this,"Data Not Found", Toast.LENGTH_LONG).show();
    }
}

Answer 1

您的应用崩溃了，因为您正在Activity进行doInBackground()切换操作。将以下代码从doInBackground()更改为onPostExecute()，

Intent i = new Intent(getApplicationContext(),AboutUs.class);
startActivity(i);
finish();

执行以下操作，

 protected void onPostExecute(String file_url) {
            pDialog.dismiss();
            if(flag==1)
             Toast.makeText(MainActivity.this,"Please Enter Correct informations",Toast.LENGTH_LONG).show();
            else{
             Intent i = new Intent(getApplicationContext(),AboutUs.class);
             startActivity(i);
             finish();
               }
        }

如何使用json使用Web服务

1 个答案: