我创建了一个view T3
:
cliid fullname MgrName Mgrid
12 V1 Vas 1
13 V2 xyz 2
14 V3 abc 4
15 V4 Vas 1
16 V5 Vas 1
和另一个view as T4
:
AckNo clifullname
1222 V1
1333 V2
2334 V3
1533 V4
1600 V5
我想对这些视图执行连接以产生如下结果:
AckNo cliid fullname MgrName Mgrid
1222 12 V1 Vas 1
1333 13 V2 xyz 2
2334 14 V3 abc 4
1533 15 V4 Vas 1
1600 16 V5 Vas 1
到目前为止,我已经尝试了以下查询,但是我想要解决这个问题的重复记录。
select T4.AckNo,T3.cliid,T3.FullName,T3.MgrName,T3.MgrId
from T3
join T4 On T4.cliFullName=T3.FullName
答案 0 :(得分:1)
select AckNo,cliid,fullname,MgrName,Mgrid from
(
select *,rn=ROW_NUMBER()over(order by cliid) from T3 --your view
)x,
(
select *,rn1=ROW_NUMBER()over(order by AckNo) from T4 --your view
)y
where x.rn=y.rn1
//你可以像这样创建视图
create view tiger as
select AckNo,cliid,fullname,MgrName,Mgrid from
(
select *,rn=ROW_NUMBER()over(order by cliid) from tabl1 --your view(T3)
)x,
(
select *,rn1=ROW_NUMBER()over(order by AckNo) from table2 --your view(T4)
)y
where x.rn=y.rn1
select * from tiger