Question

我正在逐行读取文本文件，每行都格式化为

05/20/2014 10:18:28 am

m/d/y h:m:s

如何将此与当前日期进行比较并选择不少于一周的日期？这是我到目前为止所做的，但我想知道是否还有其他更简单的方法：

$arr = explode(' ',trim($line));
$fword = explode("/", $fword);
$fword =  $arr[0];
list($m,$d,$y) = explode("/", $line);
mm= date('m');
dd = date('d');

顺便说一句，我正在以这种格式写文本文件：

$date = date('m/d/Y h:i:s a', time());

Answer 1

您可以使用strtotime。

$current_time = strtotime(date('d-M-Y g:i:s A'));

$one_week = 3600 * 24 * 7;

// your file code
$fword =  $arr[0]; // assuming that $fword has file date.

// $fword = str_replace("/", "-", $fword);
$file_time = strtotime($fword);

$diff = $current_time - $file_time;
if($diff>$one_week)
{
   echo " date : ".$fowrd." is older than one week <br/>";
}
else 
{
   echo " date : ".$fowrd." is not older than one week <br/>";  
}

Answer 2

忘记字符串操作和日期函数，改为使用DateTime类 - 它是为这类任务设计的。

//Current time
$now = new DateTimeImmutable();
//One week ago
$oneWeekAgo = $now->sub(new DateInterval('P1W'));

//Read whole file into array
$lines = file('test.txt', \FILE_SKIP_EMPTY_LINES | \FILE_IGNORE_NEW_LINES);

foreach ($lines AS $line) {
    $date = DateTime::createFromFormat('m/d/Y h:i:s a+', $line);
    //Here you can compare your dates like any other variables
    if ($date > $oneWeekAgo) {
        //Current date is less than 1 week "old"
    }
    if ($date < $oneWeekAgo) {
        //Current date is more than 1 week "old"
    }
}

对于不同的日期/时间段，请参阅http://www.php.net/manual/en/dateinterval.construct.php。例如，如果你想在＆＃34; 1天前和＃34;做同样的事情，它将是 - ＆gt; sub（新的DateInterval（＆＃39; P1D＆＃39;）），＆＃34; 1未来一年＆＃34;将是 - ＆gt; add（new DateInterval（＆＃39; P1Y＆＃39;））。

Answer 3

只需使用日期和strtotime方法

$t = '05/02/2014 10:18:28 am';
$aWeekLater = date('Y-m-d H:i:s', strtotime($t.' -1 week'));
$curDate = date('Y-m-d H:i:s');

if ($curDate < $aWeekLater) {
    echo 'xxx';
} else {
    echo 'yyy';
}

Answer 4

if (60*60*24*7+time() < strtotime(trim($line))) {
    // greater than 1 week in future
} else {
    // within 1 week from now
}

将当前日期与文本文件中写入的日期进行比较不到一周

4 个答案: