我正在努力填充选择表单元素。这是我到目前为止的语法。它不会抓取program.title并填充ngOptions。
<select ng-model="student.program" ng-options="program.title for program in programList.title">
<option value="">Select A Program</option>
</select>
以下是我在Firebase上的数据的基本JSON结构：
{
"-JNIBeRDAuNN9c7SGZ91" : {
"location" : "Online",
"director" : "Shawn Clark",
"title" : "Web Design & Development"
},
"-JNIBuaQlWyEyWRjONPa" : {
"location" : "Online",
"director" : "Walen Morrow",
"title" : "Graphic Design"
},
"-JNIBmIwasMYOPRPupHl" : {
"location" : "Campus",
"director" : "Tracy Monohan",
"title" : "Web Design & Development"
},
"-JNKGPNj-lGzqHJ92RTD" : {
"location" : "Online",
"director" : "Glen Speedy",
"title" : "Theory of Animation & Physics"
},
"-JNK9oTO97PfSo-0wQfY" : {
"location" : "Campus",
"director" : "John Myers",
"title" : "Instructional Design & Technology"
},
"-JNIC3Tldo-Qi3ru2ph7" : {
"location" : "Campus",
"director" : "George Narrow",
"title" : "Graphic Design"
},
"-JNK8cdgdHKjH2meKl9x" : {
"location" : "Online",
"director" : "Stacy McNally",
"title" : "Instructional Design & Technology"
}
}
答案 0 :(得分：2)
我相信你在寻找
<select ng-model="student.program" ng-options="program.title for (id, program) in programList"><option value="">Select A Program</option></select>
您的JSON的根对象是一个对象，而不是一个数组。 See angular documentation for object data sources
答案 1 :(得分：-2)
请尝试以下代码。
应该有效：
<select ng-model="student.program" ng-options="program.title for program in programList"><option value="">Select A Program</option></select>
由于