Question

我有一个很好的Chain SELECT，但是我希望能够将数据从搜索记录表单推送到包含Chain SELECT的表单，我怎么可能在这个中使用SELECTED = SELECTED码？

我的select.class.php

<?php
class SelectList {
    public function ShowMake($searchboilermake) {
        include "./core/cnn.php";
        $sql = "SELECT * FROM blr_boilermake";
        $res = mysql_query($sql);
        $boilermake = '<option value=""></option>';
        while($row = mysql_fetch_array($res)) {
            $boilermake .= '<option value="' . $row['BoilerID'] . '"';
            $boilermake .= ($row['BoilerID']==$searchboilermake) ? " selected='selected' " : "";
            $boilermake .= '>' . $row['BoilerMake'] . '</option>';
        }
        return $boilermake;
    }

    public function ShowModel() {
        include "../core/cnn.php";
        $sql = "SELECT * FROM blr_boilermodel WHERE BoilerModel IS NOT NULL AND BoilerID = $_POST[id]";
        $res = mysql_query($sql);
        $boilermodel = '<option value="0"></option>';
        while($row = mysql_fetch_array($res)) {
            $boilermodel .= '<option value="' . $row['ModelID'] . '">' . $row['BoilerModel'] . '</option>';
        }
        return $boilermodel;
    }
}
$opt = new SelectList();
?>

从我在我页面上的表单中我使用它来引入select.class.php以获取boilermake字段

<label>Manufacturer</label>
<select class="select2_category form-control" data-placeholder="Choose a Category" tabindex="1" id="boilermanufacturer" name="boilermanufacturer">
<?php echo $opt->ShowMake($_REQUEST['boilermanufacturer']); ?>
</select>

这是我的boilermodel字段

<label>Model</label>
<select class="select2_category form-control" data-placeholder="Choose a Category" tabindex="1" id="boilermodel" name="boilermodel">
 <option value=""></option>
</select>

在其他更直接和标准SELECT的SELECTS中，我使用下面的内容，但我如何在下面对我的Chain SELECT进行调整？

<div class="form-group">
<label>Fuel Type</label>
<?php $fueltype = db::getInstance()->query('SELECT * FROM lkup_fueltype');
if(!$fueltype->count()) { 
    echo 'Problem'; 
} else { ?> 
<select class="select2_category form-control" data-placeholder="Choose a Category" tabindex="1" id="propertyfueltype" name="propertyfueltype">
<?php foreach ($fueltype->results() as $fueltype) { ?>
<option value="<?php echo $fueltype->ID; ?>"<?php echo $fueltype->ID == $searchboilerfueltype ? "selected" : ""; ?>><?php echo $fueltype->PropertyFuelType; ?></option> <?php } } ?>
</select>

我尝试使用它，但在运行代码时没有选择SELECTED行

$boilermake .= '<option value="' . $row['BoilerID'] . '" "' . $row['BoilerID'] . '" == $searchboilermake ? "selected" : "">' . $row['BoilerMake'] . '</option>';

我应该做些什么/或者我该怎么做才能让它发挥作用？

Answer 1

问题是你试图在字符串中使用boolean / ternary表达式。这显然不会用这样的字符串进行评估。

$boilermake .= '<option value="' . $row['BoilerID'] . '"';
$boilermake .= ($row['BoilerID']==$searchboilermake) ? " selected='selected' " : "";
$boilermake .= '>' . $row['BoilerMake'] . '</option>';

修改：您需要修复函数ShowMake以传递$searchboilermake作为参数。

功能定义：

public function ShowMake($searchboilermake) {

致电功能：

<?php echo $opt->ShowMake($_REQUEST['boilermanufacturer']); ?>

SELECTED = SELECTED＆amp;链选择PHP

1 个答案: