Question

我有一个如下字符串：

NSString *a = @"* This is a text String \n * Followed by another text String \n * Followed by a third"

我需要将其打印为三行。现在，我希望其中的Asterix点加粗。所以我试过了：

NSMutableAttributedString *att = [[NSMutableAttributedString alloc] initWithString:a];
[att addAddtribute:NSFontAttributeName value:SOMEBOLDFONT range:[a rangeOfString:@"*"]];

但这只是第二和第三个星号的加粗。我怎么把它们全都搞清楚？

Answer 1

rangeOfString只返回一个范围而不是所有范围。循环并设置所有范围

NSRange range = [event1 rangeOfString:@"*"];

while (range.length > 0)
{
    [att addAddtribute:NSFontAttributeName value:SOMEBOLDFONT range:[a rangeOfString:@"*"]];
     //check for the presence of * in the rest of the string
    range = [[event1 substringFromIndex:(range.location + range.length)] rangeOfString:@"*"];
}

Answer 2

正如其他人所提到的，你需要遍历字符串以返回多个范围。这可行：

NSString *a = @"* This is a text String \n* Followed by another text String \n* Followed by a third";
NSMutableAttributedString *att = [[NSMutableAttributedString alloc] initWithString:a];
NSRange foundRange = [a rangeOfString:@"*"];

while (foundRange.location != NSNotFound)
{
    [att addAttribute:NSFontAttributeName value:[UIFont boldSystemFontOfSize:20.0f] range:foundRange];

    NSRange rangeToSearch;
    rangeToSearch.location = foundRange.location + foundRange.length;
    rangeToSearch.length = a.length - rangeToSearch.location;
    foundRange = [a rangeOfString:@"*" options:0 range:rangeToSearch];
}

[[self textView] setAttributedText:att];

Answer 3

每次在字符串中遇到“*”字符时都需要找到。

为此，您可以使用found in this related question之类的例程。

您唯一需要从代码中删除此行：

[mutableAttributedString setTextColor:color range:NSMakeRange(range.location, 1)];

并将其替换为您的代码：

 [mutableAttributedString addAttribute:NSFontAttributeName value:SOMEBOLDFONT range:NSMakeRange(range.location, 1)];

如何在NSString中加粗字符的多个实例？

3 个答案: