Question

我正在尝试将以下c＃类序列化为XML

[DataContract]
public class LatLonPoint
{
  [DataMember(IsRequired = true, Order = 1)]
  public float Lat { get; set; }

  [DataMember(IsRequired = true, Order = 2)]
  public float Lon { get; set; }

  [DataMember(EmitDefaultValue = false, Order = 3)]
  public DateTime? OptimalTime { get; set; }
}

当我使用以下代码

序列化此类时

public static string GetLatLonPointXml(LatLonPoint data)
{
  XmlSerializer xmlSerializer = new XmlSerializer(data.GetType());

  using ( StringWriter stringWriter = new StringWriter() )
  {
    xmlSerializer.Serialize(stringWriter, data);
    return stringWriter.ToString();
  }
}

我得到以下结果

<?xml version="1.0" encoding="utf-16"?>
<LatLonPoint xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
  <Lat>30</Lat>
  <Lon>-97</Lon>
  <OptimalTime xsi:nil="true" />
</LatLonPoint>

为什么在将EmitDefaultValue添加到DataMember属性时会输出OptimalTime？我已经能够使用EmitDefaultValue来处理字符串，但不能用其他任何东西。非常感谢你的帮助。

Answer 1

@Joe：谢谢！更改为DataContractSerializer修复了此问题。现在我的序列化代码如下所示：

public static string GetXml(LatLonPoint data)
{
  DataContractSerializer serializer = new DataContractSerializer(data.GetType());

  using ( MemoryStream stream = new MemoryStream() )
  {
    serializer.WriteObject(stream, data);
    byte[] bytes = stream.ToArray();
    return Encoding.UTF8.GetString(bytes, 0, bytes.Length);
  }
}

XML输出现在是：

<LatLonPoint xmlns="http://schemas.datacontract.org/2004/07/Mnc.Service.Model.External" xmlns:i="http://www.w3.org/2001/XMLSchema-instance">
  <Lat>30</Lat>
  <Lon>-97</Lon>
</LatLonPoint>

感谢Joe和Mr.EXE！

Answer 2

试试这个：

 [DataContractFormat]

 public class LatLonPoint
{

    public float Lat { get; set; }


    public float Lon { get; set; }


    public DateTime? OptimalTime { get; set; }
}

EmitDefaultValue = false仅适用于字符串

2 个答案: