替换文本，但忽略文档中的某个字符串

Question

我有一个大字符串：Hello <span class="ashakd">my</span> name is <bob>!

我有第二个字符串：llo my name

我想要用<span class="ashakd">llo my name</span>

替换它

我需要replace()，好像<span class="ashakd">和</span>不存在，但它们会被字符串替换，因此最终结果为：He<span class="ashakd">llo my name</span> is <bob>!

PS：<bob>存在，因此您无法忽略两个＆gt;之间的任何文字，它必须明确忽略<span class="ashakd">和</span>

非常抱歉，如果这令人困惑。如果这令人困惑，请让我更清楚

修改

抱歉不清楚，但它必须只替换我的替换内。所以如果原始字符串是：Hello <span class="ashakd">my</span> name is <bob><span class="ashakd">hello</span>!

结果将是：He<span class="ashakd">llo my name</span> is <bob><span class="ashakd">hello</span>!

Answer 1

这可能对原始字符串过于具有破坏性，但我提出了这个解决方案：

var a = 'Hello <span class="ashakd">my</span> name is <bob>!';
var searchString = 'llo my name';
// remove all <span> and </span> tags,  you may not want to remove any and all span tags???
a = a.replace(/<\/?span[^>]*?>/g,'');
a = a.replace(searchString,"<span class='ashakd'>"+searchString+"</span>");

这样做是删除所有span标签，然后搜索你的姓名＆＃34; llo我的名字＆＃34;搜索字符串，并用span标记包装它。

既然你说你不熟悉正则表达式，那么这里有一个描述：

/<\/?span[^>]*?>/g

<\/?   means match on '<' and then optionally a /.  This matches both the start and end tags, i.e. <span...> and </span>

[^>]*?  means match any character that is NOT > in a non-greedy fashion, i.e. stop matching at the first > found.

The final /g means 'global', which means match <span> and </span> as many times as possible.