Question

我正在使用以下文档：http://flask.pocoo.org/docs/patterns/streaming/ 以下是追溯的很好部分

  File "(my template)", line 85, in block "scripts"
    {{ super() }}
  File "/usr/local/lib/python2.7/site-packages/flask_bootstrap/templates/bootstrap/base.html", line 27, in block "scripts"
    <script src="{{bootstrap_find_resource('jquery.js', cdn='jquery')}}"></script>
  File "/usr/local/lib/python2.7/site-packages/flask_bootstrap/__init__.py", line 93, in bootstrap_find_resource
    config = current_app.config
  File "/usr/local/lib/python2.7/site-packages/werkzeug/local.py", line 338, in __getattr__
    return getattr(self._get_current_object(), name)
  File "/usr/local/lib/python2.7/site-packages/werkzeug/local.py", line 297, in _get_current_object
    return self.__local()
  File "/usr/local/lib/python2.7/site-packages/flask/globals.py", line 34, in _find_app
    raise RuntimeError('working outside of application context')

以下是我的代码：

@app.route('/render', methods=['GET', 'POST'])
def render():
  form = MyForm(request.form)
  if request.method == 'POST'
    def generate():
      for i,v in enumerate(my_data):
        yield (i,v)
    return Response(stream_template('results.html'), form=form, results=stream_with_context(generate))
  else:
    return render_template('advanced.html')

def stream_template(template_name, **context):
    app.update_template_context(context)
    t = app.jinja_env.get_template(template_name)
    rv = t.stream(context)
    rv.enable_buffering(5)
    return rv

虽然我注意到文档明确说Without the stream_with_context() function you would get a RuntimeError at that point.，但我不明白为什么这会导致运行时错误，尽管已经包含了stream_with_context

Answer 1

我不完全熟悉您在stream_template方法中所做的事情，但根据示例，您需要在stream_with_context的第一个参数上使用Response，不在模板参数周围。

如果您需要根据模板进行流式传输，那么模板可能需要成为生成函数的一部分。

stream_with_context和stream_template引发RuntimeError

1 个答案: