Question

bash脚本产生以下输出：

Computer_1 Netcom 1 Status_ok
Computer_1 Netcom 2 Status_ok
Computer_1 Netcom 3 Status_ok
Computer_1 Netcom 4 Status_ok
Computer_1 Netcom 5 Status_ok
Computer_1 Netcom 6 Status_ok
Computer_1 Netcom 7 Status_ok
Computer_1 Netcom 8 Status_ok
Computer_2 Netcom 9 Status_ok
Computer_2 Netcom 10 Status_ok
Computer_2 Netcom 11 Status_ok
Computer_2 Netcom 12 Status_ok
Computer_2 Netcom 13 Status_ok
Computer_2 Netcom 14 Status_ok
Computer_2 Netcom 15 Status_ok
Computer_2 Netcom 16 Status_ok
Computer_3 Netcom 17 Status_ok
Computer_3 Netcom 18 Status_ok
Computer_3 Netcom 19 Status_ok
Computer_3 Netcom 20 Status_ok
Computer_3 Netcom 21 Status_ok
Computer_3 Netcom 22 Status_ok
Computer_3 Netcom 23 Status_ok
Computer_3 Netcom 24 Status_ok
Computer_4 Netcom 25 Status_ok
Computer_4 Netcom 26 Status_ok
Computer_4 Netcom 27 Status_ok
Computer_4 Netcom 28 Status_ok
Computer_4 Netcom 29 Status_ok
Computer_4 Netcom 30 Status_ok
Computer_4 Netcom 31 Status_ok
Computer_4 Netcom 32 Status_ok

但是，我需要将输出组批量格式化为四列：

Computer_1          Computer_2          Computer_3          Computer_4
Netcom 1 Status_ok  Netcom 9 Status_ok  Netcom 17 Status_ok Netcom 25 Status_ok
Netcom 2 Status_ok  Netcom 10 Status_ok Netcom 18 Status_ok Netcom 26 Status_ok
Netcom 3 Status_ok  Netcom 11 Status_ok Netcom 19 Status_ok Netcom 27 Status_ok
Netcom 4 Status_ok  Netcom 12 Status_ok Netcom 20 Status_ok Netcom 28 Status_ok
Netcom 5 Status_ok  Netcom 13 Status_ok Netcom 21 Status_ok Netcom 29 Status_ok
Netcom 6 Status_ok  Netcom 14 Status_ok Netcom 22 Status_ok Netcom 30 Status_ok
Netcom 7 Status_ok  Netcom 15 Status_ok Netcom 23 Status_ok Netcom 31 Status_ok
Netcom 8 Status_ok  Netcom 16 Status_ok Netcom 24 Status_ok Netcom 32 Status_ok

实现以下输出的高性能解决方案是什么？

Answer 1

pr可以执行按列格式化。我在这里使用awk来拆分列标题：

script.sh | 
awk '
    $1 != prev {print $1; prev=$1} 
    {for (i=2; i<=NF; i++) {$(i-1)=$i}; NF--; print}
' | 
pr -t4 -w84 |
expand

输出

Computer_1           Computer_2           Computer_3           Computer_4
Netcom 1 Status_ok   Netcom 9 Status_ok   Netcom 17 Status_ok  Netcom 25 Status_ok
Netcom 2 Status_ok   Netcom 10 Status_ok  Netcom 18 Status_ok  Netcom 26 Status_ok
Netcom 3 Status_ok   Netcom 11 Status_ok  Netcom 19 Status_ok  Netcom 27 Status_ok
Netcom 4 Status_ok   Netcom 12 Status_ok  Netcom 20 Status_ok  Netcom 28 Status_ok
Netcom 5 Status_ok   Netcom 13 Status_ok  Netcom 21 Status_ok  Netcom 29 Status_ok
Netcom 6 Status_ok   Netcom 14 Status_ok  Netcom 22 Status_ok  Netcom 30 Status_ok
Netcom 7 Status_ok   Netcom 15 Status_ok  Netcom 23 Status_ok  Netcom 31 Status_ok
Netcom 8 Status_ok   Netcom 16 Status_ok  Netcom 24 Status_ok  Netcom 32 Status_ok

Answer 2

这可能是一个更好的lottttt，但单向

其中$ 1是bash脚本的输出。

我使用awk删除第一个字段。然后迭代行数并从输出中读取每第8行。然后将换行符翻译成标签，使其看起来很整洁。

显然，如果您有不断变化的记录或行数，或者您可以在脚本开头设置它们并替换我的硬编码数字。

#!/bin/bash

echo -e "Computer_1\t\tComputer_2\t\tComputer_3\t\tComputer_4"
line=$(awk '{ print $2, $3, $4 }' $1)

for ((i = 1 ; i < 9 ; i++)); do

    linez=$(sed -n $i'~8p' <<< "$line")
    linez2=$(tr "\n" "\t" <<< "$linez")
    echo "$linez2"

done

Shell脚本 - 输出列格式

2 个答案: