我有3张桌子,如:
parent(id, name)
children(id, data, parent_id, timestamp)
table_votes(id, user_id, child_id)
我想从children
表中获取具有特定parent_id
的所有行,同时显示table_votes
中每个行的出现次数。
我尝试了类似以下的内容,但似乎无法正常工作,我想我会遗漏children
中没有条目的所有行table_votes
SELECT
`children`.`id`,
`children`.`data`,
`children`.`parent_id`,
`children`.`timestamp`,
COUNT(`v`.`children_id`)
FROM `children` LEFT JOIN `table_votes` `v` ON `children`.`id` = `v`.`child_id`
WHERE `children`.`parent_id` = 20 ORDER BY `timestamp` ASC
任何暗示我做错了什么?
提前谢谢
答案 0 :(得分:3)
几种可能的选择,其中之一:
SELECT * ,
(SELECT count(*)
FROM `table_votes`
WHERE `children`.`id` = `table_votes`.`child_id`) AS `Count`
FROM `children`
WHERE `parent_id` = 20
您也可以使用查询,但必须添加GROUP BY
:
SELECT
`children`.`id`,
`children`.`data`,
`children`.`parent_id`,
`children`.`timestamp`,
COUNT(`v`.`children_id`)
FROM `children` LEFT JOIN `table_votes` `v` ON `children`.`id` = `v`.`child_id`
WHERE `children`.`parent_id` = 20
GROUP BY `children`.`id`, `children`.`data`, `children`.`parent_id`, `children`.`timestamp`,
ORDER BY `timestamp` ASC
答案 1 :(得分:2)
1)带有subselect的解决方案:
SELECT
children.id,
children.data,
children.parent_id,
children.timestamp,
(select count(*) from table_votes children.id = table_votes.child_id) as cntVotes
FROM
children
WHERE
children.parent_id = 20
ORDER BY
children.timestamp ASC
2)分组解决方案:
SELECT
children.id,
children.data,
children.parent_id,
children.timestamp,
count(table_votes.id) as cntVotes
FROM
children
LEFT JOIN
table_votes ON children.id = v.child_id
WHERE
children.parent_id = 20
GROUP BY
children.id,
children.data,
children.parent_id,
children.timestamp
ORDER BY
children.timestamp ASC
答案 2 :(得分:0)
我不确定我是否正确理解了您的问题,但对我而言,您似乎想要计算tables_votes中不是儿童的子女数量。尝试以下方法:
select id, data, parent_id, timestamp, child_id
from table_votes join children on children_id.id = table_vote.child_id
where child_id = (select count(child_id) from table_vote)
and parent_id = '20'