Question

我是ruby的新手，我想知道如何拆分包含特殊字符的元素。

我有以下数组：

my_array = ["sh.please-word", ".things-to-do" , "#cool-stuff", "span.please-word-not"]
my_array.slice!(0..1)
puts my_array 

=>#cool-stuff
=>span.please-word

我想让它拆分不以点（。）或（＃）开头的数组元素，并返回如下列表：

.please-word
.things-to-do
#cool_stuff
.please-word-not

我试图将切片方法用于完美的字符串，但是当我尝试使用数组元素时，它不起作用。

这是我到目前为止所做的。

list_of_selectors = []
file = File.open("my.txt") 
file.each_line do |line|
  list_of_selectors << line.split(' {')[0] if line.start_with? '.' or line.start_with? '#' 
end 
while line = file.gets
  puts line 
end
i = 0 
while i < list_of_selectors.length
  puts  "#{list_of_selectors[i]}"
  i += 1
end
list = []
list_of_selectors.each { |x| 
  list.push(x.to_s.split(' ')) 
}

list_of_selectors = list
puts list_of_selectors

list_of_selectors.map! { |e| e[/[.#].*/]}

puts list_of_selectors

Answer 1

result_array = my_array.map { |x| x[/[.#].*/] }
# => [".please-word", ".things-to-do", "#cool-stuff", ".please-word-not"]

上面使用正则表达式来提取文本，从点（.）或主题标签（#）开始，并在结果数组中返回。

之前拆分数组元素。例如li.mean-array

1 个答案: