Question

这是我第一次使用JSON，但我正在试验POST请求。

发出POST请求

当我使用asynctask + httppost

时，我的代码有效

private static final String url = "http://jsonblob.com/api/jsonBlob";

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    new PostJsonTask().execute();
}

private class PostJsonTask extends AsyncTask<Void, Void, Void> {
    @Override
    protected Void doInBackground(Void... params) {
        try {
            HttpResponse response = post();
            Header s = response.getFirstHeader("Location");
            Log.d("PostJsonTask", s.getValue());
        } catch (Exception e) {
            e.printStackTrace();
        }
        return null;
    }

    private HttpResponse post() throws Exception {
        // convert parameters into JSON object
        Map<String, String> params = new HashMap<String, String>();
        params.put("user", "Robby");
        params.put("pass", "zqdqzdqdqzd");
        JSONObject holder = new JSONObject(params);

        HttpClient client = new DefaultHttpClient();
        HttpPost post = new HttpPost(url);
        StringEntity se = new StringEntity(holder.toString());
        se.setContentType(new BasicHeader(HTTP.CONTENT_TYPE, "application/json"));
        post.setHeader("Accept", "application/json");
        post.setHeader("Content-type", "application/json");
        post.setEntity(se);
        return client.execute(post);
    }
}

使用此代码，我可以成功获取Location参数。

但是我想用Volley库做这个，我已经有了以下代码：

private static final String url = "http://jsonblob.com/api/jsonBlob";

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    RequestQueue queue = Volley.newRequestQueue(this);

    StringRequest request = new StringRequest(Request.Method.POST, url, createResponseListener(), createErrorListener()) {
        @Override
        public Map<String, String> getHeaders() throws AuthFailureError {
            Map<String, String> headers = new HashMap<String, String>();
            headers.put("Accept", "application/json");
            headers.put("Content-type", "application/json");

            return headers;
        }

        @Override
        protected Map<String, String> getParams() throws AuthFailureError {
            Map<String, String> params = new HashMap<String, String>();
            params.put("user", "Robby");
            params.put("pass", "zqdqzdqdqzd");

            return params;
        }

        @Override
        protected Response<String> parseNetworkResponse(
                NetworkResponse response) {
            Map<String, String> headers = response.headers;
            String location = headers.get("Location");
            Log.d("PostJsonTask", location);

            return super.parseNetworkResponse(response);
        }
    };

    queue.add(request);
}

private ErrorListener createErrorListener() {
    return new ErrorListener() {

        @Override
        public void onErrorResponse(VolleyError error) {
            error.printStackTrace();
        }
    };
}

private Listener<String> createResponseListener() {
    return new Listener<String>() {

        @Override
        public void onResponse(String response) {
            Log.d("PostJsonTask", response);
        }
    };
}

但这会返回代码为400的VolleyError。我该如何解决这个问题？

Answer 1

不是尝试设置标题的内容类型，而是尝试为bodyContentType设置，而在postman（web）中，您也只设置主体的内容类型

JsonObjectRequest jsonObjReq = new JsonObjectRequest(Method.POST,
        url, obj,
        new Response.Listener<JSONObject>() {

            @Override
            public void onResponse(JSONObject response) {
                Log.d("Response", response.toString());

            }
        }, new Response.ErrorListener() {
                @Override
                public void onErrorResponse(VolleyError error) {
                    Log.d("Error", error.toString());
                }
        })

    @Override
    public String getBodyContentType() {
        return "application/json";
    }
};

Answer 2

请勿使用getParams覆盖。

相反，使用这些参数创建一个JSON，并像JsonObjectRequest中一样提供请求的主体（或者只使用JsonObjectRequest代替StringRequest），例如< / p>

JSONObject jsonObject = new JSONObject();
try {
    jsonObject.put("user", "Robby");
    jsonObject.put("pass", "zqdqzdqdqzd");
} catch (JSONException e) {
    // handle exception (not supposed to happen)
}

StringRequest request = new StringRequest(Request.Method.POST, url, createResponseListener(), createErrorListener()) {

    // your code without getParams

    @Override
    public byte[] getBody() {
        try {
            return jsonObject.toString.getBytes("utf-8");
        } catch (UnsupportedEncodingException uee) {
            // not supposed to happen
            return null;
        }
    }
}

Volley POST请求，400错误

2 个答案: