Question

我有一个包含3个系列的条形图，但我不能更改他们的名字，我只有y1 y2 y2，而不是代码中我自己的名字。根据示例bar chart我看到，我应该使用Multi-columnBarChart，但我该怎么做呢？这里是来自Multi-columnBarChart示例的评论：

function multiColumnBarPlotter(e) {
  // We need to handle all the series simultaneously.
  if (e.seriesIndex !== 0) return;

  var g = e.dygraph;
  var ctx = e.drawingContext;
  var sets = e.allSeriesPoints;
  var y_bottom = e.dygraph.toDomYCoord(0);

  // Find the minimum separation between x-values.
  // This determines the bar width.
  var min_sep = Infinity;
  for (var j = 0; j < sets.length; j++) {
    var points = sets[j];
    for (var i = 1; i < points.length; i++) {
      var sep = points[i].canvasx - points[i - 1].canvasx;
      if (sep < min_sep) min_sep = sep;
    }
  }
  var bar_width = Math.floor(2.0 / 3 * min_sep);

这是我的代码：

function barChartPlotter(e) {
    var ctx = e.drawingContext;
    var points = e.points;
    var y_bottom = e.dygraph.toDomYCoord(0);

    // The RGBColorParser class is provided by rgbcolor.js, which is
    // packed in with dygraphs.
    var color = new RGBColorParser(e.color);
    color.r = Math.floor((255 + color.r) / 2);
    color.g = Math.floor((255 + color.g) / 2);
    color.b = Math.floor((255 + color.b) / 2);
    ctx.fillStyle = color.toRGB();

    // Find the minimum separation between x-values.
    // This determines the bar width.
    var min_sep = Infinity;
    for (var i = 1; i < points.length; i++) {
      var sep = points[i].canvasx - points[i - 1].canvasx;
      if (sep < min_sep) min_sep = sep;
    }
    var bar_width = Math.floor(2.0 / 3 * min_sep);

    // Do the actual plotting.
    for (var i = 0; i < points.length; i++) {
      var p = points[i];
      var center_x = p.canvasx;

      ctx.fillRect(center_x - bar_width / 2, p.canvasy,
          bar_width, y_bottom - p.canvasy);

      ctx.strokeRect(center_x - bar_width / 2, p.canvasy,
          bar_width, y_bottom - p.canvasy);
    }
    }

data = [];
var x = js_array.length;
// CONVERTATION
pass = [];
fail = [];
tree = [];
for (var i=0; i<x; i++){
    if (js_array[i] == 1) {
        pass.push(js_array[i]);
        fail.push(NaN);
        tree.push(NaN);
        }
    else  if (js_array[i] == 2) {
        pass.push(NaN);
        fail.push(js_array[i]);
        tree.push(NaN);
        }

    else if (js_array[i] == 3) {
        pass.push(NaN);
        fail.push(NaN);
        tree.push(js_array[i]);
        }
    }

// DATA
for (var i=0; i<x; i++){
    var y = x - i - 1;
    data.push([new Date(js_array_time[y]), pass[y], fail[y], tree[y]]);
    }

seriesName = ['x','PASS', 'FAIL', 'TREE']
// OPTIONS
var start = new Date(js_array_time[9]);
var stop = new Date(js_array_time[0]);
start.setMinutes(start.getMinutes() - 10);
stop.setMinutes(stop.getMinutes() + 10);

s = document.getElementById("s");

g = new Dygraph(
document.getElementById("graphdiv"),
data,
{
    width: 580,
            includeZero: true,
            animatedZooms: true,
            plotter: barChartPlotter,
    axisLineWidth: 0.001,
    //labels: seriesName,
        legend: 'always',
        title: 'Test results',
    drawYAxis:false,
    valueRange: [0.5, 3.5],
    dateWindow: [Date.parse(start), Date.parse(stop)],
    pointClickCallback: function(e, p) {
                //s.innerHTML += "<b>Point Click</b> " + p.name + ": " + p.xval + "<br/>";
        window.open('../RUNNER/_VLOGS/launch' + p.xval + '.html','_blank');
        window.open('../RUNNER/_LOGS/launch_log' + p.xval + '.txt','_blank');
                },
    //drawPoints: true,
    //drawXGrid: false,
    //drawYGrid: false,
    //fillGraph: true

    }
);

g.ready(function() {
    g.setAnnotations([
    {

    }]);
});

Answer 1

对于多个系列，您需要获得allSeriesPoints而不是points。以下是我为另一个问题提出的一个例子：

以下是jsFiddle.com >的 DEMO

绘图仪代码如下所示：

function multiColumnBarPlotter(e) {
  // We need to handle all the series simultaneously.
  if (e.seriesIndex !== 0) return;

  var g = e.dygraph;
  var ctx = e.drawingContext;
  var sets = e.allSeriesPoints;
  var y_bottom = e.dygraph.toDomYCoord(0);

  // Find the minimum separation between x-values.
  // This determines the bar width.
  var min_sep = Infinity;
  for (var j = 0; j < sets.length; j++) {
    var points = sets[j];
    for (var i = 1; i < points.length; i++) {
      var sep = points[i].canvasx - points[i - 1].canvasx;
      if (sep < min_sep) min_sep = sep;
    }
  }
  var bar_width = Math.floor(2.0 / 3 * min_sep);

  var fillColors = [];
  var strokeColors = g.getColors();
  for (var i = 0; i < strokeColors.length; i++) {
    var color = new RGBColorParser(strokeColors[i]);
    color.r = Math.floor((255 + color.r) / 2);
    color.g = Math.floor((255 + color.g) / 2);
    color.b = Math.floor((255 + color.b) / 2);
    fillColors.push(color.toRGB());
  }

  for (var j = 0; j < sets.length; j++) {
    ctx.fillStyle = fillColors[j];
    ctx.strokeStyle = strokeColors[j];
    for (var i = 0; i < sets[j].length; i++) {
      var p = sets[j][i];
      var center_x = p.canvasx;
      var x_left = center_x - (bar_width / 1.3) * (1 - j/(sets.length-1));

      ctx.fillRect(x_left, p.canvasy,
          bar_width/sets.length, y_bottom - p.canvasy);

      ctx.strokeRect(x_left, p.canvasy,
          bar_width/sets.length, y_bottom - p.canvasy);
    }
  }
}

然后我创建了2个相同数据的图表，一个使用CSV，另一个使用数组。 CSV直接在数据中提供标签，对于阵列，您可以使用labels属性更改标签：

labels: ['x', 'series1', 'series2', 'series3'],

整个图表代码将是

g2 = new Dygraph(document.getElementById("g_div2"),
                 theData,
                   {
                     // options go here. See http://dygraphs.com/options.html
                     legend: 'always',
                     labels: ['x', 'series1', 'series2', 'series3'],
                     animatedZooms: true,
                     plotter: multiColumnBarPlotter,
                     colors: ["#00A0B0", "#6A4A3C", "#CC333F", ],
                     dateWindow: [0, 8]
                 });

dygraph - 如何更改条形图的系列名称

1 个答案: