Question

目前这是我的代码：

echo "Upload: " . $_FILES["file"]["name"] . "<br>";
          echo "Type: " . $_FILES["file"]["type"] . "<br>";
          echo "Size: " . ($_FILES["file"]["size"] / 1024) . " KB<br>";
          echo "Stored in: " . $_FILES["file"]["tmp_name"] . "<br>";

  move_uploaded_file($_FILES["file"]["tmp_name"],"images/" . $_FILES["file"]["name"]);
            echo "images/" . $_FILES["file"]["name"];
            $path="images/" . $_FILES["file"]["name"];

Answer 1

$image_info = getimagesize($_FILES["file"]["tmp_name"]);
$image_width = $image_info[0];
$image_height = $image_info[1];

您可以参考：http://www.php.net/manual/en/function.getimagesize.php作为参考！

注意：在使用“getimagesize”之前，请检查上传的文件是否为图像，否则会出错。

Answer 2

试试这个：

list($width, $height, $type, $attr) = getimagesize($path);
echo "Width is : " . $width;
echo "Height is : " . $height;

如何在PHP中获取上传图像的宽度和高度

2 个答案: