Question

目前我正在尝试通过Java套接字发送文件。我可以成功发送特定文件的请求并获取文件。但是，当我尝试再次执行它而不重新启动程序时，我无法这样做。

这是我的代码：

客户端

System.out.print("What file do you want? ");
    name = consoleIn.readLine();
    int bytesRead;

    if(!name.equals("!")) {

        InputStream in = null;
        OutputStream output = null;
        DataInputStream serverData = null;

        while(!name.equals("!")) {
            socketOut.println(name);
            socketOut.flush();

            InputStream is = null;
            FileOutputStream fos = null;
            BufferedOutputStream bos = null;
            try {
                is = socket.getInputStream();
            } catch (IOException ex) {
                System.out.println("Can't get socket input stream. ");
            }

            try {
                fos = new FileOutputStream(name);
                bos = new BufferedOutputStream(fos);

            } catch (FileNotFoundException ex) {
                System.out.println("File not found. ");
            }

            byte[] bytes = new byte[4000];

            int count;

            while ((count = is.read(bytes)) != -1) {
                bos.write(bytes, 0, count);
            }
            System.out.println("Here");
            bos.flush();


            System.out.print("What file do you want? ");
            name = consoleIn.readLine();
        }    
    }

服务器

socket = serverSocket.accept();
            System.out.println("Connection accepted!");
            BufferedReader socketIn =
                    new BufferedReader(new InputStreamReader(socket.getInputStream()));
            //PrintWriter socketOut = new PrintWriter(socket.getOutputStream());
            String name;
            BufferedReader fileIn;
            String line;
            name = socketIn.readLine();
            System.out.println(name);

            while((!name.equals("!")) && (!name.equals("*"))) {

                File file = new File(rootDirectory, name);

                byte[] bytes = new byte[4000];
                FileInputStream fis = new FileInputStream(file);
                BufferedInputStream bis = new BufferedInputStream(fis);
                BufferedOutputStream out = new BufferedOutputStream(socket.getOutputStream());

                int count;

                System.out.println("Sending: " + name);
                while ((count = bis.read(bytes)) != -1) {
                    out.write(bytes, 0, count);
                }
                out.flush();
                System.out.println("Sent");
                name = socketIn.readLine();
                System.out.println(name);
            }

我没有被提示输入我的第二个请求。

Answer 1

我对FileServer:69感到好奇 - 您正在接受另一个阻止所有进程的用户套接字。只需从服务器中删除此行，所有这些都应该有效。

更重要的是，我建议你为每个接受的套接字创建一个新线程。

Java客户端和服务器 - 多个请求

1 个答案: