Question

在我的应用程序中有3种类型的信息：

BrokerInfo
BrokerBank
BrokerDocument

用户应在将所有数据保存到数据库之前填写所有数据。

我到目前为止所尝试的内容如下，但事务有问题，例如在没有BrokerBank记录的情况下创建BrokerInfo记录。存储一切或什么都没有的正确方法是什么？

public function add() {
        if ($this->request->is('post')) {
            $this->BrokerInfo->begin();
            $this->BrokerInfo->create();
            $this->request->data['BrokerInfo']['id'] = String::uuid();
            $this->request->data['BrokerInfo']['account_status_id'] = 1;
            $this->request->data['BrokerInfo']['db_status_id'] = 1;
            if ($this->BrokerInfo->save($this->request->data)) {

                $this->BrokerBank->begin();
                $this->BrokerBank->create();
                $this->request->data['BrokerBank']['broker_info_id'] = $this->request->data['BrokerInfo']['id'];
                if($this->BrokerBank->save($this->request->data))
                {
                    $this->BrokerDocument->begin();
                    $this->BrokerDocument->create();
                    if($this->BrokerDocument->save($this->request->data))
                    {
                        $this->BrokerInfo->commit();
                        $this->BrokerBank->commit();
                        $this->BrokerDocument->commit();

                        $this->Session->setFlash(__('The Broker information has been saved'), 'flash_success');
                        $this->redirect(array('action' => 'index'));
                    }
                    else
                    {
                        $this->BrokerInfo->rollback();
                        $this->BrokerBank->rollback();
                        $this->BrokerDocument->rollback();
                        $this->Session->setFlash(__('The customer information could not be saved. Please, try again.'), 'flash_fail');
                    }
                }
                else 
                {
                    $this->BrokerInfo->rollback();
                    $this->BrokerBank->rollback();
                    $this->Session->setFlash(__('The customer information could not be saved. Please, try again.'), 'flash_fail');
                }

            }
            else 
            {
                $this->BrokerInfo->rollback();
                $this->Session->setFlash(__('The customer information could not be saved. Please, try again.'), 'flash_fail');
            }
        }

Answer 1

使用saveAssociated

问题中的代码是已经存在的东西的用户土地实现：saveAssociated

Model :: saveAssociated（array $ data = null，array $ options = array（））

用于一次保存多个模型关联的方法。

使用saveAssociated问题中的代码不过是：

public function add() {
    if (!$this->request->is('post')) {
        return;
    }

    $this->BrokerInfo->create();
    $this->request->data['BrokerInfo']['account_status_id'] = 1;
    $this->request->data['BrokerInfo']['db_status_id'] = 1;
    if ($this->BrokerInfo->saveAssociated($this->request->data)) {
        $this->Session->setFlash(...);
        return $this->redirect(array('action' => 'index'));
    }

    $this->Session->setFlash(...);
}

请注意，没有必要指定uuid（在保存后使用$model->id来引用新的id），并且当前的硬编码默认值最好放在模型beforeSave方法中，除非它们的值是控制器 - 逻辑依赖。

如何使用关联数据保存记录

1 个答案:

使用saveAssociated