Question

我一直收到这个编译错误。我尝试将类节点更改为结构但这似乎没有帮助。我知道我现在的btree课程都是公开的，我还没有创建getroot功能来访问btree的私人数据成员。

小时。文件：

#ifndef BTREE_H
#define BTREE_H

#include <fstream>
#include <string>
#include <iostream>

using namespace std;

class node {

    node& operator = (node* nd1)
    { this->left = nd1->left;
     this->right = nd1->right;
     this->data = nd1->data;
     return *this;}

public:
    node(const std::string data);
    std:: string data;
    node *left, *right;

};

class btree {
public:
    //class node;
    btree();
    void addRoot(const std::string d);
    void addLeft(node *nd, const std::string &data);
    void addRight(node *nd, const std::string &data);


    //node *getRoot();

    //std::string get(node *node);

public:
    //btree::
        node *root;

};

.cpp文件：

#include <fstream>
#include <sstream>
#include <string>

using namespace std;

btree::btree(){
    root=NULL;}

void btree::addRoot(const std:: string d) {root = new node(d);}



void btree::addLeft(node *nd, const string &data) {
    if (nd == 0) throw "Attempt addLeft on null";
    if (nd->left != 0) throw "Attempt addLeft on nd with existing left child";
    nd->left = new node(data);}



void btree::addRight(node *nd, const string &data) {
    if (nd == 0) throw "Attempt addRight on null";
    if (nd->right != 0) throw "Attempt addRight on nd with existing right child";
    nd->right = new node(data);
}

演示文件：

#include "btree.h"

#include <iostream>
#include <fstream>
#include <sstream>
#include <string>


using namespace std;

int main(){
    char answer;
    string question, animal;

    btree game;
    game.addRoot("Elephant");
    bool again=true;
    bool solved;
    solved=false;

    while(!solved){

        while(again){
            cout<<game.root<<"?"<<endl;
            cout<<"Y/N"<<endl;
            cin>>answer;
                    if( answer == 'y' || 'Y'){

                                if(!(game.root->left)){
                                        cout<<"Game over. Computers are smart!!! ;)"<<endl;
                                        solved=true;
                                        again = false;}
                                    else
                                            game.root= game.root->left;
                                            again = true;
                    }
                        else 
                                //user clicked no check if leaf to the right 
                                    if (!(game.root->right)){
                                    cout<<"No more answers, You WIN!!!!"<<endl;
                                    cout<<"What question could I have asked instead?"<<endl;
                                    cin>>question;

                                    string temp= game.root->data;
                                    game.root->data= question;

                                    cout<<"What is the animal?"<<endl;
                                    cin>>animal;

                                    game.addLeft(game.root, animal);
                                    game.addRight(game.root, temp);


                                    solved=true;
                                    again = false;}


                                            else{
                                                node *move= game.root->right;
                                                game.root = move;

                                                solved=false;
                                                again= true;}
        }
        }


return 0;
}

Answer 1

我对此不太确定，因为自从我上次使用C ++以来已经有一段时间了，但是你也不应该实现节点头文件吗？特别是构造函数，因为我看到原型在那里，但我没有看到任何定义。你还可以指出错误的确切行吗？

决策搜索树中的LINK错误2019和1120

1 个答案: