Question

我正在使用存储过程来登录用户，我需要返回玩家ID。我测试时提供的名称和密码是正确的，结果返回1但是playerID保持为NULL

`player_login` (
username TEXT CHARACTER SET utf8,
txtPassword TEXT CHARACTER SET utf8,
OUT playerID INTEGER,
OUT result INTEGER
)
BEGIN
DECLARE password TEXT DEFAULT player_hash_password(txtPassword);
DECLARE num INTEGER DEFAULT 0;
   SELECT PlayerID INTO playerID
    FROM players
    WHERE (LOWER(players.PlayerName)=LOWER(username) OR  LOWER(players.PlayerEmail)=LOWER(username))
    AND players.PlayerPassword = password
    LIMIT 1;
...

为什么未将PlayerID选入playerID？ PlayerID是一个非空的自动增量整数。

Answer 1

您的参数与列名称匹配，这是MySQL存储过程的长期问题。为参数使用前缀，例如：

`player_login` (
p_username TEXT CHARACTER SET utf8,
p_txtPassword TEXT CHARACTER SET utf8,
OUT p_playerID INTEGER,
OUT p_result INTEGER
)
BEGIN
DECLARE p_password TEXT DEFAULT player_hash_password(p_txtPassword);
DECLARE num INTEGER DEFAULT 0;
   SELECT p_PlayerID = playerID
    FROM players p
    WHERE (LOWER(p.PlayerName)=LOWER(p_username) OR  LOWER(p.PlayerEmail)=LOWER(p_username))
    AND p.PlayerPassword = p_password
    LIMIT 1;
.

选择不适用于存储过程

1 个答案: