到目前为止,我已经为计算器制作了用户界面,以及在开关盒中处理的按钮。到目前为止还不错。
我的问题是如何才能让应用程序识别输入到textview中的第一个数字,然后再按下该数字设置为num1?
我的代码如下:
public class MainActivity extends Activity {
// variables declared to hold buttons and text field.
Button btn0, btn1, btn2, btn3, btn4, btn5, btn6, btn7, btn8, btn9, btnc,
btnplus, btnd, btnpnt, btnequal;
TextView text;
int num1, num2;
String input;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
// reference and assign the resources for the view elements
btn0 = (Button) findViewById(R.id.button0);
btn1 = (Button) findViewById(R.id.button1);
btn2 = (Button) findViewById(R.id.button2);
btn3 = (Button) findViewById(R.id.button3);
btn4 = (Button) findViewById(R.id.button4);
btn5 = (Button) findViewById(R.id.button5);
btn6 = (Button) findViewById(R.id.button6);
btn7 = (Button) findViewById(R.id.button7);
btn8 = (Button) findViewById(R.id.button8);
btn9 = (Button) findViewById(R.id.button9);
btnc = (Button) findViewById(R.id.buttonc);
text = (TextView) findViewById(R.id.textView1);
btnd = (Button) findViewById(R.id.button16);
btnpnt = (Button) findViewById(R.id.buttonpnt);
btnplus = (Button) findViewById(R.id.buttonplus);
// add the click listeners
btn0.setOnClickListener(onClickListener);
btn1.setOnClickListener(onClickListener);
btn2.setOnClickListener(onClickListener);
btn3.setOnClickListener(onClickListener);
btn4.setOnClickListener(onClickListener);
btn5.setOnClickListener(onClickListener);
btn6.setOnClickListener(onClickListener);
btn7.setOnClickListener(onClickListener);
btn8.setOnClickListener(onClickListener);
btn9.setOnClickListener(onClickListener);
btnc.setOnClickListener(onClickListener);
btnd.setOnClickListener(onClickListener);
btnpnt.setOnClickListener(onClickListener);
btnplus.setOnClickListener(onClickListener);
btnequal.setOnClickListener(onClickListener);
}
private OnClickListener onClickListener = new OnClickListener() {
@Override
public void onClick(View v) {
// TODO Auto-generated method stub
switch (v.getId()) {
case R.id.button0:
text.setText(text.getText().toString()
+ btn0.getText().toString());
break;
case R.id.button1:
text.setText(text.getText().toString()
+ btn1.getText().toString());
break;
case R.id.button2:
text.setText(text.getText().toString()
+ btn2.getText().toString());
break;
case R.id.button3:
text.setText(text.getText().toString()
+ btn3.getText().toString());
break;
case R.id.button4:
text.setText(text.getText().toString()
+ btn4.getText().toString());
break;
case R.id.button5:
text.setText(text.getText().toString()
+ btn5.getText().toString());
break;
case R.id.button6:
text.setText(text.getText().toString()
+ btn6.getText().toString());
break;
case R.id.button7:
text.setText(text.getText().toString()
+ btn7.getText().toString());
break;
case R.id.button8:
text.setText(text.getText().toString()
+ btn8.getText().toString());
break;
case R.id.button9:
text.setText(text.getText().toString()
+ btn9.getText().toString());
break;
case R.id.button16:
String contents = text.getText().toString();
if (contents.length() > 1) {
text.setText(contents.substring(0, contents.length() - 1));
} else {
text.setText("");
}
break;
case R.id.button16:
text.setText("");
break;
case R.id.buttonpnt:
String dot = ".";
String concat = text.getText() + dot;
text.setText(concat);
break;
case R.id.buttonplus:
String operator = "+";
String concatt = text.getText() + operator;
text.setText(concatt);
break;
}
}
};
我不明白如何告诉android在添加之前输入的第一个数字被存储为num1。从那里计算将是一块蛋糕。
任何心智敏锐的人都可以帮助我
非常感谢你的时间
答案 0 :(得分:1)
当用户按下按钮时,您的TextView会保留该号码,例如用户按2 5 1然后按加号按钮。在你的案例R.id.buttonplus中,TextView内容将是你的num1。所以你可以这样做:
case R.id.buttonplus:
int num1 = Integer.parseInt(text.getText().toString());
text.setText(text.getText() + "+");