Question

当我点击一个按钮时，我需要设置这个布局，我的java就像：

Layout propLayout = (Layout) findViewById(R.id.properLayout);

    public void propsBtn(View view) {
propLayout.setVisiblity(View.Visible);
}

我知道布局线完全错了！如果有人能告诉我如何正确设置，我将非常感激：）

这是我的XML：

<FrameLayout xmlns:android="http://schemas.android.com/apk/res/android"
xmlns:tools="http://schemas.android.com/tools"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:background="@color/mainBackGround"
tools:context="com.myapplication2.app.MainActivity">

<LinearLayout
    android:layout_width="match_parent"
    android:layout_height="match_parent">

    <RelativeLayout
        android:layout_width="match_parent"
        android:layout_height="match_parent"
        android:padding="8dp">

...contents...

    </RelativeLayout>

</LinearLayout>

<LinearLayout
    android:layout_width="match_parent"
    android:layout_height="match_parent"
    android:visibility="gone"
    android:id="@+id/properLayout">

    <RelativeLayout
        android:orientation="horizontal"
        android:layout_width="match_parent"
        android:layout_height="300dp"
        android:layout_gravity="bottom"
        android:padding="8dp">

...contents...           

    </RelativeLayout>

</LinearLayout>

Answer 1

DerGolem给出了正确的答案，但他随后删除了它，所以我现在在这里报告：

//First we set visibility value of interested layout either to gone, visible or invisible
android:visibility="gone"

然后在onCreate下写如：

//specify the button that has to handle visibility  
ImageButton properties = (ImageButton) findViewById(R.id.propBtn);

//And the layout we want to change is visibility
final LinearLayout propLayout = (LinearLayout) findViewById(R.id.properLayout);

            properties.setOnClickListener
            (
                    new View.OnClickListener()
                    {
                        public void onClick(View v)
                        {
                            if (propLayout.getVisibility() == View.VISIBLE)
                            {
                                propLayout.setVisibility(View.INVISIBLE);
                            }
                            else
                            {
                                propLayout.setVisibility(View.VISIBLE);
                            }
                        }
                    }
            );

Answer 2

另一种切换方式，如果有人喜欢

，则用较少的线条切换

// button to click
ImageButton properties = (ImageButton) findViewById(R.id.propBtn);

// and LinearLayout to toggle
final LinearLayout propLayout = (LinearLayout) findViewById(R.id.properLayout);

properties.setOnClickListener(new View.OnClickListener() {
    @Override
    public void onClick(View v) {
        propLayout.setVisibility((propLayout.getVisibility() == View.VISIBLE) 
          ? View.INVISIBLE 
          : View.VISIBLE);
    }
});

Answer 3

试试这个：

int counter = 0;
    TextVeiw tv = (TextView) findViewById(R.id.textView);
Button button = (Button ) findViewById(R.id.but);
button.setOnClickListener(new OnClickListener() {

public void onClick(View v) {
    // TODO Auto-generated method stub
    counter++;
    if(counter%2==0){
        tv.setVisibility(View.Visible);//show
    } else {
        tv.setVisibility(View.Gone);//hide
    }
}
});

Answer 4

您需要在要切换的布局上设置OnClickListener()。然后在侦听器内部检查布局是否可见。如果是，则将其可见性设置为View.INVISIBLE。否则，您将其设置为View.VISIBLE。

在onClick上切换布局的可见性

4 个答案: