Question

我的文件内容如下:(这是nmap输出）

Nmap scan report for x.x.x.x
Host is up (0.12s latency).
PORT   STATE SERVICE
23/tcp open  telnet
| telnet-brute: 
|   Accounts
|     var1:var2
|   Statistics
|     Performed 5 guesses in 3 seconds, average tps: 1
|   
|_ ERROR: Too many retries, aborted ...

Nmap scan report for y.y.y.y
Host is up (0.17s latency).
PORT   STATE SERVICE
23/tcp open  telnet
| telnet-brute: 
|   Accounts
|     var3:var4
|   Statistics
|_    Performed 2 guesses in 13 seconds, average tps: 0

Nmap scan report for z.z.z.z
Host is up (0.19s latency).
PORT   STATE SERVICE
23/tcp open  telnet
| telnet-brute: 
|   Accounts
|     No valid accounts found

我想提取这种模式：

x.x.x.x   var1:var2
y.y.y.y   var3:var4

我尝试的是：

#!/bin/bash

NmapResult=$1

rm oooo
while read line
do
    if [[ "$line" == *Nmap* ]]; then
        OUT=$(grep "Nmap" -A6)
        if [[ "$OUT" == *valid* ]]; then
            continue
        else
            grep "Nmap" -A6 >> oooo
            echo
        fi
    fi
done < $NmapResult

但这不是真的，也不完全是我想要的。

你能帮我解决这个问题吗？

由于

Answer 1

$ awk -v RS= -F'\n' '{n=split($1,a,/ /); sub(/\| */,"",$7); print a[n], $7}' file
x.x.x.x var1:var2
y.y.y.y var3:var4
z.z.z.z No valid accounts found

或者如果要排除第3行输出，您可能需要：

$ awk -v RS= -F'\n' '$7~/:/{n=split($1,a,/ /); sub(/\| */,"",$7); print a[n], $7}' file
x.x.x.x var1:var2
y.y.y.y var3:var4

Answer 2

这可能适合你（GNU sed）：

sed -nr '/^Nmap.* /{s///;h};/Accounts/{n;H;g;s/\n\|\s*/ /;/:/p}' file

这将捕获所需的行并将其转换为所需的格式。

在bash中提取文件的内容

2 个答案: