我无法在我的代码中找到一些表格,并且需要一些帮助,因为我已经尝试了但是它回来了"解析错误:语法错误,意外'< ;'在第27行和第34行的C:\ xampp \ htdocs \ search_go.php中。那么我可以获得如何插入表格的帮助吗?
<?php
//capture search term and remove spaces at its both ends if the is any
$searchTerm = trim($_GET['keyname']);
//check whether the name parsed is empty
if($searchTerm == "")
{
echo "Enter name you are searching for.";
exit();
}
//database connection info
$host = "localhost"; //server
$db = "calendar"; //database name
$user = "root"; //dabases user name
$pwd = ""; //password
//connecting to server and creating link to database
$link = mysqli_connect($host, $user, $pwd, $db);
//MYSQL search statement
$query = "SELECT * FROM caltbl WHERE evtDate LIKE '%$searchTerm%'";
$results = mysqli_query($link, $query);
<table>
/* check whether there were matching records in the table
by counting the number of results returned */
if(mysqli_num_rows($results) >= 1)
{
$output = "";
while($row = mysqli_fetch_array($results))
{
<tr>
$output .= "date: " . $row['evtDate'] . "<br />";
$output .= "Name: " . $row['patient'] . "<br />";
$output .= "Course: " . $row['patientId'] . "<br />";
}
echo $output;
}
else
echo "There was no matching record for the name " . $searchTerm;
?>
答案 0 :(得分:1)
您不能只在PHP代码中插入HTML标记:
然而,您可以直接使用echo
将其发送出去:
echo "<table>";
while($row = mysqli_fetch_array($results))
{
$output = "<tr>";
// <tr> This is the problem line.
$output .= "<tr>";
$output .= "<td>date: " . $row['evtDate'] . "<br /></td>";
$output .= "<td>Name: " . $row['patient'] . "<br /></td>";
$output .= "<td>Course: " . $row['patientId'] . "<br /></td>";
$output .= "</tr>";
echo $output;
}
此外,您没有关闭<tr>
。我添加了一些额外的片段,使每个字段成为表中的TD,然后关闭该行。