Question

我有3个实体 - TUser，TRequest和TComment。 TUser到TRequest，关系1到很多。对TComment的请求，与许多人的关系。我想计算每个TUser的评估。最初我在TRequest中有一个评估专栏，我有这个查询正常工作：

Query query = em.createQuery("select hiredAgency, sum(r.assessment)/(count(r.assessment)), "
                        + "count(r.assessment) "
                        + "from TAgency hiredAgency join hiredAgency.executedRequests r "
                        + "group by hiredAgency.tUserId, hiredAgency.address, hiredAgency.city, hiredAgency.information,"
                        + "hiredAgency.website")

现在评估结果在TComment中。我尝试了以下查询：

Query query = em.createQuery("select r.hiredAgency, " +
                        "sum(u.assessment)/(count(u.assessment)), " +
                        "count(u.assessment) " +
                        "from TRequest r join r.requestComments u " +
                        "group by r.hiredAgency.tUserId, r.hiredAgency.address, r.hiredAgency.city, r.hiredAgency.information," +
                        "r.hiredAgency.website");
List<Object[]> list = query.getResultList();

但是Hibernate给了我错误：

Caused by: org.hibernate.exception.SQLGrammarException: could not extract ResultSet
..
Caused by: java.sql.SQLException: ORA-00979: not a GROUP BY expression

这是我的实体。 TRequest：

public class TRequest implements java.io.Serializable {

    private Set<TComment> requestComments = new HashSet<TComment>(0);
    private TAgency hiredAgency;

    @ManyToOne(fetch = FetchType.LAZY)
    @JoinColumn(name = "HIRED_AGENCY_ID")
    public TAgency getHiredAgency() {
        return this.hiredAgency;
    }

    public void setHiredAgency(TAgency hiredAgency) {
        this.hiredAgency = hiredAgency;
    }

    @OneToMany(fetch = FetchType.LAZY, mappedBy = "tRequest")
    public Set<TComment> getRequestComments() {
        return requestComments;
    }

    public void setRequestComments(Set<TComment> requestComments) {
        this.requestComments = requestComments;
    }
}

TComment：

public class TComment implements java.io.Serializable {
    private int assessment; // +get and set methods
    private TRequest tRequest;

    @ManyToOne(fetch = FetchType.LAZY)
    @JoinColumn(name = "T_REQUEST_ID", nullable = false)
    public TRequest gettRequest() {
        return tRequest;
    }

    public void settRequest(TRequest tRequest) {
        this.tRequest = tRequest;
    }
}

TAgency：

 public class TAgency implements java.io.Serializable {
        private Long tUserId;
        private TUser tUser;private String website;
        private String city;
        private String address;
        private String information;
        private Set<TRequest> executedRequests = new HashSet<TRequest>(0);
        private Set<TAgencyEventType> tAgencyEventTypes = new HashSet<TAgencyEventType>(
                0);

        //+ get and set methods
        @OneToMany(fetch = FetchType.LAZY, mappedBy = "hiredAgency")
        public Set<TRequest> getExecutedRequests() {
            return executedRequests;
        }

        public void setExecutedRequests(Set<TRequest> executedRequests) {
            this.executedRequests = executedRequests;
        }
    }

ADDED

的DDL：

create table T_REQUEST
(
  id              NUMBER(19) not null,
  hired_agency_id NUMBER(19)
)

create table T_COMMENT
(
  id               NUMBER(19) not null,
  t_request_id     NUMBER(19) not null,
  assessment       NUMBER(10)
)

create table T_AGENCY
(
  t_user_id   NUMBER(19) not null,
  address     VARCHAR2(150 CHAR),
  city        VARCHAR2(60 CHAR) not null,
  information VARCHAR2(512 CHAR) not null,
  website     VARCHAR2(150 CHAR)
)

我想查询返回我的TAENCE对象（hiredAgency），从所有向其提出请求的人员收到的平均评估结果以及评估它的人数（给予评估）。

我无法理解我没有做的正确。

如何重写此HQL查询以正常工作

0 个答案: