使用频道ID列表，例如：
channel_ids = [＆＃39; UC6nSFpj9HTCZ5t-N3Ra3-HB＆＃39; UC6nSFpjSEBUCZ5t-N3Ra3-HB＆＃39; UC6nrst90rsd3Z5t-N3Ra3-HC＆＃39;＆＃39; UC6nSFpjd329th0rt -tuTH3-HA＆＃39;]
我想使用YouTube数据API v3检索所有这些频道的50个最新视频上传内容，使用尽可能少的http请求和尽可能少的时间。
我目前的做法是：
from apiclient.discovery import build
youtube = build('youtube', 'v3', developerKey=key)
channel_ids = ['UC6nSFpj9HTCZ5t-N3Ra3-HB', 'UC6nSFpjSEBUCZ5t-N3Ra3-HB', 'UC6nrst90rsd3Z5t-N3Ra3-HC', 'UC6nSFpjd329th0rt-tuTH3-HA']
videos_by_channel = {}
for channel_id in channel_ids:
search_response = youtube.search().list(part="id",
type='video',
order='date',
channelId=channel_id,
maxResults=50).execute()
videoIds = []
for search_result in search_response.get("items", []):
if search_result["id"]["kind"] == "youtube#video":
videoIds.append(search_result['id']['videoId'])
search_response = youtube.videos().list(
id=",".join(videoIds),
part="id,snippet"
).execute()
videos_by_channel[channel_id] = search_response
它有效，但使用了大量的服务器调用，并且速度并不快。我已经阅读了文档，但无法找到更快的方法，任何想法？