Question

我是（非常）新的MySQL。原谅我缺乏知识......

我正在制作一个曲棍球统计数据库，我需要将所有助攻和所有目标加在一起以获得“总积分”。我已经发现了两个问题，但我无法弄清楚如何将两者相加。以下是查询：

select player_id, count(*) 
from(select * from 1st_assists
union
select * from 2nd_assists) as tem
join players on tem.fk_player_id=players.player_id
group by fk_player_id
order by count(*) desc

select player_id, count(*)
from goals_for
join shots_for on goals_for.fk_shot_for_id=shots_for.shot_for_id
join players on shots_for.fk_player_id=players.player_id
group by player_id
order by count(*) desc;

如何将这两个查询合并为一个并获得两个计数的总和？

以下是每个查询的结果

Total Assists
player_id   count(*)
79      24
55      22
45      17
90      16
40      15
65      15
37      13
1       13
20      11
84      11
64      10
27      9
93      7
8       5
24      3
57      1

Goals
player_id   count(*)
90      38
37      28
40      19
55      13
45      11
1       8
24      8
20      8
84      8
27      6
8       5
79      4
65      4
93      1
64      1

Answer 1

这是未经测试的，但请你试试这个：

select p.player_first_name, p.player_last_name, (count1+count2) as total_count
from
(select player_id, count(*) count1
from(select * from 1st_assists
union
select * from 2nd_assists) as tem
join players on tem.fk_player_id=players.player_id
group by fk_player_id
order by count(*) desc) q1
left join
(select player_id, count(*) count2
from goals_for
join shots_for on goals_for.fk_shot_for_id=shots_for.shot_for_id
join players on shots_for.fk_player_id=players.player_id
group by player_id) q2
ON q1.player_id=q2.player_id
left join player p ON q1.player_id=p.player_id
order by (count1+count2) desc;

MySQL总和两个查询的计数

1 个答案: