Question

使用webview javascriptInterface在Android 4.2.2中运行的应用程序在Android 2.3.3中无效。

它有targetSdkVersion =“19”

和Build属性为4.2

我创建了2.3.3的模拟器和设备3.7“WVGA。

OnCreate Here -

@JavascriptInterface
@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    vWebview = (WebView) findViewById(R.id.vWebview);
    btnView = (Button) findViewById(R.id.btnView);
    txtView = (TextView) findViewById(R.id.txtView);

    vWebview.setWebChromeClient(new WebChromeClient());
    vWebview.setWebViewClient(new WebViewClient());

    try {
        if ("2.3".equals(Build.VERSION.RELEASE)) {
         javascriptInterfaceBroken = true;
        }
        } catch (Exception e) {
        // Ignore, and assume user javascript interface is working correctly.
        }

        // Add javascript interface only if it's not broken
        if (!javascriptInterfaceBroken) {
            vWebview.addJavascriptInterface(new JScriptInterface(),
                    "AndroidFunction");
        }



    WebSettings websetting = vWebview.getSettings();
    websetting.setJavaScriptEnabled(true);
    Log.d("Main", "Called");
    vWebview.loadUrl("file:///android_asset/sample.html");
    btnView.setOnClickListener(new OnClickListener() {

        @Override
        public void onClick(View v) {
            // TODO Auto-generated method stub

            //vWebview.loadUrl("javascript:showAndroidToast('Hello')");
            try{
            runOnUiThread(new Runnable() {
                @Override
                public void run() {
                    vWebview.loadUrl("javascript:showAndroidToast('Hello')");
                }
            });
        }
        catch(Exception ee){
            Log.d("Exception", "Called" + ee.toString());

        }
        }
    });

}

JsInterface -

public class JScriptInterface {

    public JScriptInterface() {
        // TODO Auto-generated constructor stub
    }



    public void showToast(String toast) {
        try{
        Log.d("JS", "Called" + toast);
        // txtView.setText(toast);
        Toast.makeText(MainActivity.this, toast, Toast.LENGTH_LONG).show();
        }
        catch(Exception ee){
            Toast.makeText(MainActivity.this, ee.toString(), Toast.LENGTH_LONG).show(); 

        }
    }



}

Answer 1

我想你可能碰到了this known issue。以下是解决问题的方法：Handling Android 2.3 WebView’s broken AddJavascriptInterface

致original poster here

的信用

将来，请考虑更详细地描述您的问题。＆＃34;哪个不起作用＆＃34;我不知道这个问题，所以我只是用Google搜索＆＃34; javascriptinterface 2.3.3＆＃34; - 再说一次，你可以自己完成。

<强> UPD 您需要将解决方法中的方法作为覆盖到WebViewClient。对于您的代码，它看起来应该是这样的：

vWebview.setWebChromeClient(new WebChromeClient());

try {
   if ("2.3".equals(Build.VERSION.RELEASE)) {
      javascriptInterfaceBroken = true;
   }
} catch (Exception e) {
   // Ignore, and assume user javascript interface is working correctly.
}
// Add javascript interface only if it's not broken
if (!javascriptInterfaceBroken) {
    vWebview.addJavascriptInterface(new JScriptInterface(),
            "AndroidFunction");
}

if (!javaScriptInterfaceBroken) vWebview.setWebViewClient(new WebViewClient());
else {
    vWebview.setWebViewClient(new WebViewClient() {
        // And here you put the code from the article
        @Override
        public void onPageFinished(WebView view, String url) { ... }

        @Override
        public boolean shouldOverrideUrlLoading(WebView view, String url) { ... }
    });
}

Answer 2

请检查设备而不是模拟器。当我在Android 2.3.6中检查时，它运行良好。不幸的是我没有得到任何与我们的模拟器相同的2.3.3设备。如果有人有设备，请检查并确认我。非常感谢您的宝贵意见。

Android中的Webview工作在4.2+而不是2.3.3

2 个答案: