在Laravel中使用Ajax,在控制台中返回404 Not Found

时间:2014-05-16 16:54:32

标签: php jquery ajax laravel-4

我尝试发送搜索查询并通过ajax显示结果。出于某种原因,当我提交搜索时,我在控制台中收到404 Not Found错误消息。任何提示或指示将不胜感激!

更新:只是为了澄清网址不是foo / local / bar / ...,我只是把这些东西保密,因为我是偏执的大声笑。路线被要求,这是唯一涉及的路线:

/*Home Page*/
    Route::get('/', array(
    'as'    => 'home',
    'uses'  => 'HomeController@home'
    ));

以下是控制台错误日志:

POST http://foo/local/bar/public/ 404 (Not Found) jquery.js:9597

Object 
   {readyState: 4, getResponseHeader: function, getAllResponseHeaders: function, 
   setRequestHeader: function, overrideMimeType: function…}              home.js:137

   error                                                                 home.js:138

   Not Found                                                             home.js:139

JS:

$(document).ready(function(){
    $("#search_form").submit(function(e) {
        e.preventDefault();

        //form_data
        var data = $('#search_form').serializeArray();
        $.ajax({
            url: window.location,
            type: "POST",
            data: data,
            success: function(data){
                $("#search_results").html($search);
            },
            error: function(xhr, status, error){
                console.log(xhr);
                console.log(status);
                console.log(error);
                $("search_results").html("Failure");
            }
        });
    });
});

控制器:

public function post_index() {
        $search_table   = Input::get('search_table');
        $search_column  = Input::get('search_column');
        $search_input   = Input::get('search_input');

        $search = DB::table($search_table)->where($search_column, 'LIKE', "%{$search_input}%")->get();
        echo json_encode($search);
        exit;
    }

查看:

<form id="search_form" method="POST" action="" >    
    <select id="search_table" class="search_table">
        <option value = ''>Search</option>
        <option value = 'commissions'>Search commissions</option>
    </select>   

        <div class="search_box" id="search_column_div">
            <select id='search_column' name='search_column'>
                 <option value='select'>by ...</option>
                 <option value='street_address'>by street address</option>
                        </select>
        </div>

        <div id="search_input_div">
            <input id='search_input' name='search_input' class='search_input' placeholder='Enter Street Address'/>
        </div>

<input type="submit" class="button expand radius" id="search_button"/>
</form>

1 个答案:

答案 0 :(得分:1)

我可以立即看到您的代码存在两个问题。您的路由正在侦听GET请求,但您在AJAX调用中使用POST请求。第二个问题是您已经错误地命名了控制器功能。您正在使用较旧的Laravel 3语法,但您已在问题中标记了Laravel 4。使用Laravel 4 RESTful控制器函数命名约定,您的函数名称应为postIndex()