Question

我真的在搜索所有内容和所有地方，但无论如何，无论我尝试过什么，我的这段代码都不会起作用。所以我在SQL服务器上创建了一个数据库并将其链接，测试它，非常有用。好的，问题是当我试图在网站文本框中插入数据并将数据复制/传输到我的数据库表中时。所以我现在只得到一个错误，说'Exception unhandeld并且必须声明标量变量“@f_name”。如果有人可以提供帮助，我将不胜感激？感谢。

 private void Save(string hfname, string hlname, string hemail, string hcomment)
        {
            SqlConnection myConn = new SqlConnection(GetConnectionString());
            String sql = "INSERT INTO helpdesk (First_Name, Last_Name, Email, Comments) VALUES " + " (@f_name, @l_name, @email, @comment)";
            SqlCommand cmd = new SqlCommand(sql, myConn);
            ITDBDataset itdbDataSet = new ITDBDataset();
            SqlDataAdapter dataAdapter;
            try
            {

                myConn.Open();
                dataAdapter = new SqlDataAdapter(cmd);
                dataAdapter.Fill(itdbDataSet);
                myConn.Close();

                SqlParameter[] param = new SqlParameter[6];
                //para,[0]
                param[0] = new SqlParameter("@f_name", System.Data.SqlDbType.VarChar, 50);
                param[1] = new SqlParameter("@l_name", System.Data.SqlDbType.VarChar, 50);
                param[2] = new SqlParameter("@email", System.Data.SqlDbType.VarChar, 30);
                param[3] = new SqlParameter("@comment", System.Data.SqlDbType.VarChar, 600);

                param[0].Value = hfname;
                param[1].Value = hlname;
                param[2].Value = hemail;
                param[3].Value = hcomment;

                cmd.CommandType = System.Data.CommandType.Text;
                cmd.ExecuteNonQuery();
                //SqlDataReader reader = cmd.ExecuteReader();

            }
            catch (System.Data.SqlClient.SqlException ex)
            {
                string msg = "Not Added, check context!";
                msg += ex.Message;
                throw new Exception(msg);
            }
            //finally
            //{
            //    myConn.Close();
            //}
        }

对可能出错的任何建议？

Answer 1

您忘记将参数添加到命令中，并在调用方法之前关闭连接。我建议你使用：

 private void Save(string hfname, string hlname, string hemail, string hcomment)
    {
        SqlConnection myConn = new SqlConnection(GetConnectionString());
        String sql = "INSERT INTO helpdesk (First_Name, Last_Name, Email, Comments) VALUES " + " (@f_name, @l_name, @email, @comment)";
        SqlCommand cmd = new SqlCommand(sql, myConn);
        ITDBDataset itdbDataSet = new ITDBDataset();
        SqlDataAdapter dataAdapter;
        try
        {

            myConn.Open();
            dataAdapter = new SqlDataAdapter(cmd);
            dataAdapter.Fill(itdbDataSet);


            SqlParameter[] param = new SqlParameter[6];
            //para,[0]
            param[0] = new SqlParameter("@f_name", System.Data.SqlDbType.VarChar, 50);
            param[1] = new SqlParameter("@l_name", System.Data.SqlDbType.VarChar, 50);
            param[2] = new SqlParameter("@email", System.Data.SqlDbType.VarChar, 30);
            param[3] = new SqlParameter("@comment", System.Data.SqlDbType.VarChar, 600);

            param[0].Value = hfname;
            param[1].Value = hlname;
            param[2].Value = hemail;
            param[3].Value = hcomment;

            cmd.Parameters.AddRange(param);//add the parameters
            cmd.CommandType = System.Data.CommandType.Text;
            cmd.ExecuteNonQuery();
            //SqlDataReader reader = cmd.ExecuteReader();
           myConn.Close();
        }

Answer 2

我建议你使用AddWithValue例如

SqlConnection myConn = new SqlConnection(GetConnectionString());
String sql = 
     "INSERT INTO helpdesk (First_Name, Last_Name, Email, Comments) VALUES " + 
     " (@f_name, @l_name, @email, @comment)";
SqlCommand cmd = new SqlCommand(sql, myConn);

cmd.Parameters.AddWithValue("@f_name",hfname);
cmd.Parameters.AddWithValue("@l_name",hlname);
cmd.Parameters.AddWithValue("@email",hemail);
cmd.Parameters.AddWithValue("@comment",hcomment);

ITDBDataset itdbDataSet = new ITDBDataset();
SqlDataAdapter dataAdapter;
try
{
        myConn.Open();
        dataAdapter = new SqlDataAdapter(cmd);
        dataAdapter.Fill(itdbDataSet);
        myConn.Close();
}
catch (System.Data.SqlClient.SqlException ex)
{
        string msg = "Not Added, check context!";
        msg += ex.Message;
        throw new Exception(msg);
}

链接数据集与SQL服务器：失败

2 个答案: