Question

我想在JSON字符串中提取JSON数组。但我无法弄清楚如何让它发挥作用。请参考以下代码：

/* I would like to get this working */

var all_barcodes = '{"VAM12345":{"colour":"red","size":"32"},"VAM456789":{"color":"red","size":"42"}}';
var print = $.parseJSON(all_barcodes); // this fails and hence the below loop won't run
$.each( print, function( key, value ) {
var color = value['color'];
var design = value['size'];
alert(color); alert(size)
});

/* This works well */

var test_string =  '{"VAM12345":"test1","VAM456789":"test2"}';
var print_test = $.parseJSON(test_string);
$.each( print_test, function( key, value ) {
       alert(key);
       alert(value);
    });

编辑1：对不起家伙，有一个小错字。因为，我简化了原始代码中的代码。请看看精致的..解决问题。

谢谢！

Answer 1

你的字符串中有错误检查

 var all_barcodes = '{"VAM12345":{"colour":"red","size":"32"},"VAM456789":{"color":"red","size":"42"}}';

检查此代码

    var all_barcodes = '{"VAM12345":{"colour":"red","size":"32"},"VAM456789":{"color":"red","size":"42"}}';
    var print = $.parseJSON(all_barcodes); // this fails and hence the below loop won't run
    $.each( print, function( key, value ) {
        var color = value['color'];
        var design = value['size'];
        alert(color); 
        alert(design);// variable name is design not size
    });

    /* This works well */

    var test_string =  '{"VAM12345":"test1","VAM456789":"test2"}';
    var print_test = $.parseJSON(test_string);
    $.each( print_test, function( key, value ) {
       alert(key);
       alert(value);
    });

Answer 2

我看到你的JSON有2个错误。这就是为什么它无法解析

"size","32"应为"size":"32"
"size","42"应为"size":"42"

下次尝试http://jsonlint.org

在JSON字符串中提取JSON数组

2 个答案: