from Tkinter import *
a = Tk()
canvas = Canvas(a, width = 500, height = 500)
canvas.pack()
canvas.create_rectangle(0,0,100,100)
现在我们如何删除已创建的矩形???
编辑:
这是关于我正在创建的游戏。这是一个简单的游戏,如果球击中阻挡,阻挡应该消失。但如果我做了这样的事情:
class Block:
def __init__(self,canvas,color):
self.canvas = canvas
self.id = canvas.create_rectangle(10,10,110,20,fill=color )
self.id1 = canvas.create_rectangle(115,10,215,20,fill=color)
self.id2 = canvas.create_rectangle(220,10,320,20,fill=color)
self.id3 = canvas.create_rectangle(325,10,425,20,fill=color)
self.id4 = canvas.create_rectangle(430,10,530,20,fill=color)
self.id5 = canvas.create_rectangle(100,150,200,160,fill=color)
self.id6 = canvas.create_rectangle(350,150,450,160,fill=color)
self.x = 0
然后:
def hit_block(self,pos):
block_pos = self.canvas.coords(self.block.id)
List = [block_pos]
for i in List:
if pos[0] >= i[0] and pos[2] <= i[2]:
if pos[1] >= i[1] and pos[1] <= i[3]:
canvas.delete(block.id)
self.score()
global a
a += 1
return True
return False
它不起作用。那么当球击中它时你能帮我删除阻挡吗?
答案 0 :(得分:13)
将create_rectangle()
分配给变量,然后在该变量上调用canvas.delete()
:
from Tkinter import *
a = Tk()
canvas = Canvas(a, width = 500, height = 500)
canvas.pack()
myrect = canvas.create_rectangle(0,0,100,100)
canvas.delete(myrect) #Deletes the rectangle
删除前的窗口:
删除后的窗口:
答案 1 :(得分:-1)
基本上他说的只是为坐标添加一些if语句,并插入A.J作为if语句的结果输入的内容。