Question

我遇到嵌套循环问题。在一年中，我希望我的循环将每年的每个数字加起来。当年份结束而不是添加去年的数字并将其添加到新的一年时，我希望它再次从0开始。

最后，它应该向我展示每年的总数，并给出我所有年份的平均值。

以下是我的样本，如果有人可以帮我完成它：

total_rain = 0
month = 12
y = 0
rain = 0
month_rain = 0
years = int(input("How many years: "))

for y in range(years):
    y += 1
    print()
    print("In the year", y,"There will be:")

    for m in range(month):
        rain = float(input('How many inch of rainfall have fallen: ')) 
    total_rain += rain
    print(month_rain)
main()

每次循环结束时，它都会添加上一年的数字。我希望新循环再次从0开始并加上数字。

Answer 1

total_rain = 0
month = 12
rain = 0
years = int(input("How many years: "))

for y in range(years):
    month_rain = 0
    print()
    print("In the year", y,"There will be:")

    for m in range(month):
        rain = float(input('How many inch of rainfall have fallen: ')) 
        month_rain += rain
    total_rain += month_rain
    print("year %s: %s" % (y, month_rain) )
print("total rain: %s" % (total_rain/years))

Answer 2

total_rain = []
months = 12
years = int(input("How many years: "))
for y in range(1, years+1):
    print("In the year", y,"There will be:")
    annual_rain = []
    for m in range(1,13):
        rain = float(input('How many inch of rainfall have fallen in month %s: ' %m))
        annual_rain.append(rain)
    total_rain.append(annual_rain)

for y,year in enumerate(total_rain, 1):
    print("Total rain in year %s: %s. Average monthly rain: %s" %(y, sum(year), sum(year)/len(year)))

Answer 3

for y in range(years):
    y += 1
    for m in range(month):
        rain = float(input('How many inch of rainfall have fallen: '))
        total_rain += rain
    print("In the year", y,"There will be:", total_rain," inches of rain")
    #reset variable
    total_rain = 0

首先，我更正了“total_rain + = rain”的缩进，因为你将它嵌套在第二个for循环之外，因此它实际上不会添加你每次输入的降雨量。

然后我所做的就是将总降雨设置为0以重置它。

它就像一个魅力，与你自己的代码非常相似。

python的嵌套循环

3 个答案: