Question

我使用下面的代码来获取触摸时单元格的位置。但是，当UICollectionView.bounds.size.width＆gt; 320，或＆gt; 640，“origin.x”经常返回＆gt; 320，例如，657,469。因为细胞内有一些图像。所以当我触摸第二页上的单元格时。返回的值X可以是368.0或其他值。

我只需要在当前视图中获取值X（320 * 480）。



UICollectionViewLayoutAttributes *attributes = [self.collectionView layoutAttributesForItemAtIndexPath:indexPath];

- (void)viewDidLoad
{
// attach long press gesture to collectionView
UILongPressGestureRecognizer *lpgr 
   = [[UILongPressGestureRecognizer alloc]
                 initWithTarget:self action:@selector(handleLongPress:)];
lpgr.minimumPressDuration = .5; //seconds
lpgr.delegate = self;
[self.collectionView addGestureRecognizer:lpgr];
}

-(void)handleLongPress:(UILongPressGestureRecognizer *)gestureRecognizer
{
if (gestureRecognizer.state != UIGestureRecognizerStateEnded) {
    return;
}
CGPoint p = [gestureRecognizer locationInView:self.collectionView];

NSIndexPath *indexPath = [self.collectionView indexPathForItemAtPoint:p];
if (indexPath == nil){
    NSLog(@"couldn't find index path");            
} else {
    // get the cell at indexPath (the one you long pressed)
    UICollectionViewCell* cell =
    [self.collectionView cellForItemAtIndexPath:indexPath];
    // do stuff with the cell
}
}

Answer 1

如果我正确理解您的问题，您的收藏视图可能会横向显示多个页面。假设这些页面是帧宽，你可以这样做：

int xVal = (int)p.x % (int)self.view.frame.size.width;

请记住，您将失去小数精度。

如何在self.view中获取UICollectionViewCell的位置？

1 个答案: