Question

我正在尝试编写一个程序来读取3个类数据文件，例如period1.txt，period2.txt。这些文件中包含3个不同学生的名字，姓氏和3个考试成绩。

数据文件的格式如下所示

Meagan. Hesse. 99. 99. 99

我的程序然后假设取平均分配并将结果和学生姓名写在另一个txt文件夹中，例如period1cgrade和period2grade

我已经尝试修复一些问题，但看起来它仍在进行中我还不确定我是否正确打开数据文件，你能不看一下那部分

def calcaverage(test1,test2,test3):   
    for count in range(test1,test2,test3):
        curraverage=0
        curraverage=((test1[count]+ test2[count]+ test3[count])/3)
        currentaverage.append(curraverage)
        if curraverage>= 90:
            grade= "A"
            lettergrades.append(grade)
        elif curraverage >= 80 and curraverage < 90:
            grade= "B"
            lettergrades.append(grade)
        elif curraverage >= 70 and curraverage < 80:
            grade= "C"
            lettergrades.append(grade)
        elif curraverage < 70:
            grade= "F"
            lettergrades.append(grade)

name=[]
test1=[]
test2=[]
test3=[]
averagescore=[]
lettergrades=[]



with open ("period1.txt", 'r') as infile:
    for line in infile:
        values = line.split()
        name.append(values[0] + ','+ values[1])
        for line in infile:
            values = line.split()
            score1=float(values[2])
            test1.append(score1)
            for line in infile:
                values = line.split()
                score2=float(values[3])
                test2.append(score2)
                for line in inline:
                    values = line.split()
                    score3=float(values[4])
                    test3.append(score3)
averagescore=calcaverage(test1,test2,test3)

print(line)

Answer 1

有人已经提交了答案，但在我看来，这是做你想做的最干净的方法......

marks = {90:'A', 80:'B', 70:'C', 0:'F'}
grades = {}

def calc_grades(infile):
    with open(infile, 'r') as f:
        for line in f.read().splitlines():
            fname, lname, g1, g2, g3 = line.split('. ')
            avg = sum(map(float, [g1, g2, g3]))/3
            name = "%s %s" % (fname, lname)
            grades[name] = marks[min(marks.keys(), key=lambda k: abs(k-avg) if avg>=k else 100)]

def put_grades(outfile):
    with open(outfile, 'w+') as f:
        f.writelines(["%s: %s\n" % (k, v) for k, v in grades.items()])

if __name__ == "__main__":
    calc_grades('period1.txt')
    put_grades('p1_grades.txt')

编辑：修正了lambda表达式

Answer 2

这里我将如何做到这一点：

FILENAMES = [("period1.txt", "period1grade.txt"), ... ]

for inpath, outpath in FILENAMES:
    with open(inpath) as infile, open(outpath, 'w') as outfile:
        for line in infile:
            if line:
                first, last, grades* = map(str.strip,line.split('.'))
                grades = map(int, grades) # maybe float?
                output = "{}. {}. {}\n".format(first, last, sum(grades)/len(grades)
                outfile.write(output)

我现在看到你必须指定一个字母等级，所以我会像你一样做，并为此写一个单独的函数

def getlettergrade(grades):
    """Returns a letter grade ["A","B","C","F"] given a list of ints as grades of 100"""
    percent = sum(grades)/len(grades)
    if grade >= 90: return "A"
    elif grade >= 80: return "B"
    elif grade >= 70: return "C"
    else: return "F"

使用python读写数据文件

2 个答案: