Question

出于某种原因，我无法完成这项工作。我有以下带有2个注册节点的XML。我只需要将<serialnumber>（脚本当前所做的）作为变量值返回，并将<id>, <qty>返回给<serialnumber>。

我可以获得＆＃34;序列号＆＃39; （请参阅下面的代码）但似乎无法获得个人<module>的循环以获取所有<id>, <qty>。我得到 对象不支持此属性或方法：＆＃39; ModuleList.length＆＃39; 响应。

===================== XML ================

<root>
<registration>
    <name>For Test</name>
    <serialnumber>1234567890</serialnumber>
    <modules>
        <module>
            <name>SERVER : A</name>
            <id>15</id>
            <qty>1</qty>
        </module>
        <module>
            <name>SERVER : B</name>
            <id>40</id>
            <qty>1</qty>
        </module>   
    </modules>
</registration> 
<registration>
    <name>For Test</name>
    <serialnumber>0987654321</serialnumber>
    <modules>
        <module>
            <name>SERVER : 1</name>
            <id>15</id>
            <qty>1</qty>
        </module>
        <module>
            <name>SERVER : 2</name>
            <id>40</id>
            <qty>1</qty>
        </module>   
        <module>
            <name>SERVER : 3</name>
            <id>15</id>
            <qty>1</qty>
        </module>
        <module>
            <name>SERVER : 4</name>
            <id>40</id>
            <qty>1</qty>
        </module>   
    </modules>
</registration>
</root>

===================== VB Script ================

Set objXML = Server.CreateObject("Msxml2.DOMDocument")

objXML.LoadXml(xmlString)

Set Root = objXML.documentElement
Set registrationList = Root.getElementsByTagName("registration")

For i = 0 to registrationList.length -1

  Set serialnumber = objXML.getElementsByTagName("serialnumber")(i)

  Set ModuleList = Root.getElementsByTagName("modules")(i)

    For x = 0 to ModuleList.length -1

        Set module = objXML.getElementsByTagName("module")(x)

        Response.Write module.text ' this is where I was expecting to stuff the array


    Next


  Response.Write serialnumber.text & " " 

Next

Set objXML = Nothing

Answer 1

XML是结构化数据，因此使用结构化方法（XPath）来处理它。重复/嵌套getElementsByTagName()松散了层次关系。在代码中：

  Dim oFS      : Set oFS      = CreateObject("Scripting.FileSystemObject")
  Dim sFSpec   : sFSpec       = goFS.GetAbsolutePathName("..\testdata\xml\so23686152.xml")
  Dim objMSXML : Set objMSXML = CreateObject("Msxml2.DOMDocument")
  objMSXML.setProperty "SelectionLanguage", "XPath"
  objMSXML.async = False
  objMSXML.load sFSpec

  If 0 = objMSXML.parseError Then
     Dim ndlReg : Set ndlReg = objMSXML.selectNodes("/root/registration")
     Dim ndReg
     For Each ndReg In ndlReg
         WScript.Echo ndReg.selectSingleNode("serialnumber").text
         Dim ndMod
         For Each ndMod In ndReg.selectNodes("modules/module")
             WScript.Echo   "  " _
                          , ndMod.firstChild.text _
                          , ndMod.selectSingleNode("id").text _
                          , ndMod.childNodes(2).text
         Next
     Next
  Else
     WScript.Echo objMSXML.parseError.reason
  End If

输出：

1234567890
   SERVER : A 15 1
   SERVER : B 40 1
0987654321
   SERVER : 1 15 1
   SERVER : 2 40 1
   SERVER : 3 15 1
   SERVER : 4 40 1

Answer 2

为什么不为此使用正则表达式？

Const ForReading = 1
Set objFSO = CreateObject("Scripting.FileSystemObject")
Set objFile = objFSO.OpenTextFile("test.xml", ForReading)

text = objFile.ReadAll

Dim serialNumber
Set objRE = New RegExp
objRE.pattern = "<serialnumber>([0-9]+)</serialnumber>"
Set matches = objRE.execute(text)
if matches.count > 0 then 
    serialNumber = matches.item(0).submatches.item(0)
end if

使用VB脚本解析XML

2 个答案: