Question

这是我的月产量报告表：

PruID Prod1 Prod2, ReportDate
001 12.5 32.4 1/1/1999
001 13.0 32.0 2/1/1999
...
002 45.2 32.4 1/1/2004
002 56.3 43.2 2/1/2004
...

我想总结一下Prod1和Prod2，以及过去12个月的Prod1＆amp; Pru2的Prod2。我写了两个单独的查询，他们正在为每个目的工作：

查询1：总结prod1＆amp; pru2 prod2

SELECT Prod.PruID, Sum(Prod.Prod1) AS CumProd1, Sum(Prod.Prod2) AS CumProd2
FROM Prod 
GROUP BY Prod.PruID;

查询2：总结过去12个月的Prod1＆amp; Prod2 by PruID

SELECT PruID, Sum(Prod1) AS Cum12MonProd1, Sum(Prod2) AS Cum12MonProd2
FROM Prod
WHERE Prod.ReportDate > DATEADD('m', -12, now())
GROUP BY PruID;

如何将2个查询组合成一个以生成如下内容：

PruID  CumProd1 CumProd2 Cum12MonProd1 Cum12MonProd2

Answer 1

此处的诀窍是从sum函数中排除您在第二个查询中过滤掉的数据，以获取已过滤的总数。

SELECT   prod.pruid,
         SUM (prod.prod1) AS cumprod1,
         SUM (prod.prod2) AS cumprod2,
         SUM (
            CASE
               WHEN prod.reportdate > dateadd ('m', -12, now ()) THEN
                  prod.prod1
               ELSE
                  NULL
            END)
            AS cum12monprod1,
         SUM (
            CASE
               WHEN prod.reportdate > dateadd ('m', -12, now ()) THEN
                  prod.prod2
               ELSE
                  NULL
            END)
            AS cum12monprod2
FROM     prod
GROUP BY prod.pruid;

Answer 2

您可以JOIN这两个子查询：

SELECT a.PurID, a.CumProd1, a.CumProd2, b.Cum12MonProd1, b.Cum12MonProd2
FROM
(

    SELECT Prod.PruID, Sum(Prod.Prod1) AS CumProd1, Sum(Prod.Prod2) AS CumProd2
    FROM Prod 
    GROUP BY Prod.PruID
) a INNER JOIN
(

    SELECT PruID, Sum(Prod1) AS Cum12MonProd1, Sum(Prod2) AS Cum12MonProd2
    FROM Prod
    WHERE Prod.ReportDate > DATEADD('m', -12, now())
    GROUP BY PruID
) b
ON a.PruID = b.PruID;

或在第二组总和中使用CASE：

SELECT 
    Prod.PruID, 
    Sum(Prod.Prod1) AS CumProd1, 
    Sum(Prod.Prod2) AS CumProd2,
    Sum(CASE WHEN Prod.ReportDate > DATEADD('m', -12, now()) THEN Prod1 ELSE 0) AS Cum12MonProd1,
    Sum(CASE WHEN Prod.ReportDate > DATEADD('m', -12, now()) THEN Prod2 ELSE 0) AS Cum12MonProd2
FROM Prod 
GROUP BY Prod.PruID;

以不同方式汇总同一列

2 个答案: