Question

我正在尝试使用以下规则编写正则表达式。

需要完成正则表达式匹配的文字：

Key: "employeeNo" with value "ABC12345" is already used.

规则：

 1. Only the number after ABC is changing.

 2. Key: "employeeNo" with value "ABC[Any Number with any length]" is
    already used.

真实案例

Key: "employeeNo" with value "ABC12345" is already used.
Key: "employeeNo" with value "ABC987858547" is already used.
Key: "employeeNo" with value "ABC7" is already used.

Falsecases

key is not used
Key: "employeeNo" with value "ABCXYZYZ" is already used.
Key: employeeNo with value ABC7 is already used.

正则表达式尝试

Key: "employeeNo" with value "ABC[0-9]+" is already used.

我还想检查引号“”。

Answer 1

看起来很简单，你需要逃避双引号。

String input = "Key: \"employeeNo\" with value \"ABC12345\" is already used.";
Pattern p = Pattern.compile("Key: \"employeeNo\" with value \"(ABC\\d+)\" is already used.");
Matcher m = p.matcher(input);
if (m.find()) {
    System.out.println(m.group());
    System.out.println(m.group(1));
}

<强>输出

Key: "employeeNo" with value "ABC12345" is already used.
ABC12345

如果您需要里面的后面引用的组（组1），只需将转义的双引号括在组括号中：(\"ABC\\d+\")。

在正则表达式中检查引号匹配

1 个答案: