Question

我有一个交易表，我想从时间差为2小时的表中提取这些交易，并在两个不同的国家/地区进行交易。我写了以下查询，但问题是它正在获取那些国家/地区相同的交易。

查询是：

SELECT DISTINCT b.* 
FROM TRANSACTION_TABLE b, TRANSACTION_TABLE a
WHERE 
    b.CARD IN (SELECT b.CARD 
                FROM TRANSACTION_TABLE b, TRANSACTION_TABLE a
                WHERE b.TYPE_TXN IN ('21') 
                    AND b.RESPONSE_TXN='00'
                    AND b.DATETIME_TXN BETWEEN DATEADD(hh,-2,GETDATE()) AND GETDATE()
                    AND b.CARD=a.CARD
                    AND b.COUNTRY<>a.COUNTRY
                GROUP BY B.CARD
                   HAVING COUNT(B.CARD)>1 )
    AND b.TYPE_TXN in ('21') 
    AND b.RESPONSE_TXN='00'
    AND b.DATETIME_TXN BETWEEN DDATEADD(hh,-2,GETDATE()) AND GETDATE()
    AND b.CARD=a.CARD
    AND b.COUNTRY<>a.COUNTRY

请指导。

由于

Answer 1

看起来你应该这样做：

select A.*
  from Transaction_Table A,
       Transaction_Table B
 where -- both transaction should have the same CARD
       (A.Card = B.Card) and
       -- ... But different countries
       -- In order to prevent duplicates > instead of <> 
       (A.Country > B.Country) and
       -- Time difference btw A and B should be less than 2 hours
       -- NB! DMBS dependent! (Oracle version implemented)
       ((Abs(A.DateTime_Txn - B.DateTime_Txn) < 2 / 24) and
       -- Other transaction filters
       (A.Type_TXN in ('21')) and
       (B.Type_TXN in ('21')) and
       (A.Response_TXN = '00') and
       (B.Response_TXN = '00')

SQL查询支持

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