Question

我正在使用CakePHP 2.3.6。在我的项目中，我必须使用一些值/ data /参数搜索用户，这些值位于几个表中，并且这些表是关联的。

协会是：

模型User.php中的

：

public $hasMany=array('Education'=>array(
                        'className'=>'Education
                        'foreignKey'=>'user_id'
                  ),
                  'Experience'=>array(
                        'className'=>'Experience',
                        'foreignKey'=>'user_id'
                  ),
                  'Employment'=>array(
                        'className'=>'Employment',
                        'foreignKey'=>'user_id'
                  ),
                  'ProfessionalQualification'=>array(
                        'className'=>'ProfessionalQualification',
                        'foreignKey'=>'user_id'
                  )
)

模型Education.php中的

：

public $belongsTo=array('User'=>array(
                        'className'=>'User',
                        'foreignKey'=>'user_id'
                    )
)

模型Experience.php中的

：

public $belongsTo=array('User'=>array(
                        'className'=>'User',
                        'foreignKey'=>'user_id'
                    )
)

模型Employment.php中的

：

public $belongsTo=array('User'=>array(
                            'className'=>'User',
                            'foreignKey'=>'user_id'
                        )
)

在模型ProfessionalQualification.php中：

public $belongsTo=array('User'=>array(
                        'className'=>'User',
                        'foreignKey'=>'user_id'
                    )
)

现在，在搜索表单（View / Users / search.ctp）中：

echo $this->Form->create('User');
echo $this->Form->input('name',array('type'=>'text'));
echo $this->Form->input('username',array('type'=>'text'));
echo $this->Form->input('address',array('type'=>'textarea'));
echo $this->Form->input('phone',array('type'=>'tel'));
echo $this->Form->input('degree',array('type'=>'text'));
echo $this->Form->input('passing_year',array('type'=>'text'));
echo $this->Form->input('title',array('type'=>'text'));
echo $this->Form->input('title.description',array('type'=>'textarea'));
echo $this->Form->input('company',array('type'=>'text'));
echo $this->Form->input('company.description',array('type'=>'textarea'));
echo $this->Form->input('certificate',array('type'=>'text'));
echo $this->Form->input('certificate.description',array('type'=>'textarea'));
echo $this->Form->submit('Search');
echo $this->Form->end();

<{1>}控制器中的

：

UsersController.php

我认为它会从数组中的所有关联表中检索我要查找的所有数据。但是，它给出了一个错误：

public function search(){
    $this->set('title_for_layout','Search User');

    if($this->request->is('post')){
       $conditions=array();
       $data=$this->request->data;
   if(!empty($data['name']))
      $conditions['name']="%".$data['name']."%";
   if(!empty($data['username']))
      $conditions['username']=$data['username'];
   if(!empty($data['address']))
      $conditions['address']='%'.$data['address'].'%';
   if(!empty($data['phone']))
      $conditions['phone']=$data['phone'];
   if(!empty($data['degree']))
      $conditions['degree']="%".$data['degree']."%";
       .
       .
       .
   if(!empty($data)){
      $users=$this->User->find('all',array('conditions'=>$conditions));
          if(!empty($users)){
             $this->Session->setFlash("Searching Users Successful");
             $this->set('users',$users);
          }else
             $this->Session->setFlash("No user found");
   }else
      $this->Session->setFlash("You didn't give any info to search for");
    }
}

在这里，＆＃34; degree＆＃34;来自表格＆＃34;教育＆＃34;。

然后，我使用Error: SQLSTATE[42S22]: Column not found: 1054 Unknown column 'degree' in 'where clause' SQL Query: SELECT `User`.`id`, `User`.`name`, `User`.`username`, `User`.`phone`, `User`.`address`, `User`.`created`, `User`.`modified` FROM `db_name`.`users` AS `User` WHERE `degree` = 'M.Sc.'。在ContainableBehavior模型中：

User.php

在public $actsAs=array('Containable');：

中

UsersController.php

当我使用它时，结果数组是：

$this->User->find('all',array('contain'=>array('Education'=>array(
                                                'conditions'=>array('Education.institution ='=>"Institute 1")
                                               ),
                                               'Employment'=>array(
                                                'conditions'=>array('Employment.employer ='=>"Employer 1")
                                               ),
                                               'ProfessionalQualification'=>array(
                                'conditions'=>array('ProfessionalQualification.certificate ='=>"Certificate 1")
                                               ),
                                               'Experience'=>array(
                                'conditions'=>array('Experience.title ='=>"Title 1")
                                               )
                         )
                 )
);

在这里，请注意，我只需要2号。数组，没有别的，但它给了我所有不相关的数据。

你能告诉我问题在哪里吗？我该怎么办？我想，我必须在特定字段中明确地给出表格名称，例如：ModelName.0.field。你觉得怎么样？

Answer 1

试试这个

  public function global_search() {
        $condition = array(
            'User.role' => array('U', 'P'),
            'User.user_status' => array('active', 'lead', 'inactive')
        );
        if ($this->request->is('post') || $this->request->is('put')) {


            $or = array(
                'PersonalInformation.first_name' => $this->request->data['User']['first_name'],
                'PersonalInformation.last_name' => $this->request->data['User']['last_name'],
                'PersonalInformation.primary_phone' => $this->request->data['User']['primary_phone'],
                'PersonalInformation.dob' => $this->request->data['User']['dob'],
                'User.email' => $this->request->data['User']['email'],
            );
            //==========This Function allow remove blank element from array=========//

            $or = array_filter($or);

            //=====End============//

            $condition = array(
                'User.role' => array('U', 'P'),
                'User.user_status' => array('active', 'lead', 'inactive'),
                'OR' => $or
            );

            $data = $this->User->find('first', array(
                'conditions' => $condition)
            );
            // pr($data); exit;
            $this->set('allusers', $data);
        }

        $data = $this->User->find('all', array(
            'conditions' => $condition)
        );
        //pr($data); exit;
        $this->set('allusers', $data);
        $this->layout = 'admin';
    }

从CakePHP中的关联模型中搜索数据

1 个答案: