Question

我在分析行时遇到一些问题。实际上我在这一行中拥有一切：

'test:[abc:123];something\r\nName=some name;phone no.: [123456]\r\nAddress: some address; another   address\r\n\r\n'

我希望这条线像这样：

test:[abc:123];something
Name=some name;phone no.: [123456]
Address: some address; another address

我试过

#from ast import literal_eval
from ast import *
a = 'test:[abc:123];something\r\nName=some name;phone no.: [123456]\r\nAddress: some address; another address\r\n\r\n'
msg = literal_eval(a)
# and
msg = eval(a)

但我得到错误。有没有其他简单的方法来解决这个问题？

Answer 1

kk = 'test:[abc:123];something\r\nName=some name;phone no.: [123456]\r\nAddress: some address; another address\r\n\r\n'
lk = "\n".join(kk.split("\r\n"))
print lk

<强>输出：

test:[abc:123];something
Name=some name;phone no.: [123456]
Address: some address; another   address

Answer 2

如果这是您生成的字符串，请尝试.splitlines()

的.split('\r\n')?

如果从文件中读取此内容，请在打开文件时尝试设置行结尾。或者使用myfile = open(filename, 'r', newline='\n\r')

打开文件

Answer 3

拆分工作正常：

    l = 'test:[abc:123];something\r\nName=some name;phone no.: [123456]\r\nAddress: some address; another   address\r\n\r\n'.split("\r\n")
    In [14]: for line in l:
   ....:         print line
   ....:     
    test:[abc:123];something
    Name=some name;phone no.: [123456]
    Address: some address; another   address

python解析字符串\ r \ n新行

3 个答案: