我使用jsf(netbeans)创建了简单的登录页面现在我想将这个简单的登录作为活动目录身份验证如何做到这一点..
****我的xhtml代码****
<h:head>
<title>LogIn</title>
<h:outputStylesheet library="css" name="style.css"/>
</h:head>
<h:body>
<h:form>
<fieldset>
<legend>LogIn</legend>
<p:messages autoUpdate="true" severity="info" closable="false" />
<div styleclass="label">
<h:outputLabel id="usernameOutputId" value="Username : " />
</div>
<div styleclass="textbox">
<h:inputText id="usernameInputId" value="#{userLogin.userName}"
required="true" requiredMessage="Enter username" size="20" />
<br/>
<span><h:message for="usernameInputId" errorClass="errorMessage" /></span>
</div>
<br/>
<div styleclass="label">
<h:outputLabel id="passwordOutputId" value="Password : " />
</div>
<div styleclass="textbox">
<h:inputSecret id="passwordInputId" value="#{userLogin.password}"
required="true" requiredMessage="Enter password" size="20" />
<br/>
<span><h:message for="passwordInputId" errorClass="errorMessage" /></span>
</div>
<br/>
<h:commandButton id="userLoginCmdBtnId" value="LOGIN"
action="#{userLogin.Process}" />
</fieldset>
</h:form>
</h:body>
</html>
**我的java代码*****
package login;
import java.sql.Connection;
import java.sql.DriverManager;
import java.sql.ResultSet;
import java.sql.Statement;
import javax.faces.application.FacesMessage;
import javax.faces.bean.ManagedBean;
import javax.faces.bean.SessionScoped;
import javax.faces.context.FacesContext;
@ManagedBean(name = "userLogin")
@SessionScoped
public class LogIn {
public String userName;
public String password;
public FacesMessage message;
public String getUserName() {
return userName;
}
public void setUserName(String userName) {
this.userName = userName;
}
public String getPassword() {
return password;
}
public void setPassword(String password) {
this.password = password;
}
public FacesMessage getMessage() {
return message;
}
public void setMessage(FacesMessage message) {
this.message = message;
}
public String Process() throws Exception {
Connection c = null;
Statement st = null;
Class.forName("org.postgresql.Driver");
c = DriverManager
.getConnection("jdbc:postgresql://localhost:5432/test",
"postgres", "admin");
c.setAutoCommit(false);
System.out.println("Opened database successfully");
st = c.createStatement();
ResultSet res = st.executeQuery( "SELECT * FROM users;" );
String sql="select * from users";
res=st.executeQuery(sql);
while(res.next())
{
System.out.println("hiii");
System.out.println(res.getString(1));
System.out.println("Uid="+userName);
if (userName.equalsIgnoreCase(res.getString(1))
&& password.equalsIgnoreCase(res.getString(2)))
{
System.out.println("Login Successful");
return "success";
}
else{
message = new FacesMessage(FacesMessage.SEVERITY_INFO, "Authentication Failed Earror.", "");
FacesContext.getCurrentInstance().addMessage(null, message);
return "failure";
}
}
return"";
}
答案 0 :(得分:1)
尝试使用LDAP协议登录Active Directory
进行登录 Hashtable<String, String> props = new Hashtable<String, String>();
String principalName = userName + "@" + "MYDOMAIN";
props.put(Context.SECURITY_PRINCIPAL, principalName);
props.put(Context.SECURITY_CREDENTIALS, password);
DirContext context = null;
context = LdapCtxFactory.getLdapCtxInstance("ldap://ad.mydomain:389", props);
System.out.println("User login successful: " );
在代码中替换正确的域和LDAP URL(和端口)。
如果你到达System.out.println行,那么登录成功,否则你会得到 javax.naming.AuthenticationException异常。