Question

我有一张名为tuition的桌子我想要检索所有学习111和不学习333的学生这是我能想到的：

http://www.sqlfiddle.com/#!2/f6411/3

stud_id | subject_id
--------------------
    1       111
    1       222
    2       222
    2       333
    3       111
    3       222
    3       333
    4       111
    4       222

输出

stud_id
-------
   1
   4

Answer 1

三种选择：

使用HAVING子句和WHERE子句：

SELECT *
FROM tution 
WHERE subject_id = 111 OR subject_id=333
GROUP BY stud_id
HAVING COUNT(DISTINCT subject_id)=1 AND subject_id<>333

结果为SQL Fiddle。

使用不带HAVING子句的WHERE子句：

SELECT *
FROM tution 
GROUP BY stud_id
HAVING COUNT(DISTINCT subject_id)=2 AND subject_id =111 AND subject_id<>333

结果为SQL Fiddle。

使用IN：

SELECT *
FROM tution
WHERE subject_id=111
AND stud_id NOT IN (SELECT stud_id FROM tution WHERE subject_id= 333)

结果为SQL Fiddle。

结果：

STUD_ID  SUBJECT_ID
1        111
4        111

Answer 2

select stud_id from tution 
where stud_id not in (select stud_id from tution t 
                  where t.subject_id = 333) 
and subject_id = 111

Fiddle

Answer 3

试试这个：

SELECT t1.stud_id FROM tuition t1 
WHERE t1.subject_id=111 
AND NOT EXISTS(SELECT 1 FROM tuition t2 
               WHERE t1.stud_id=t2.stud_id 
               AND t2.subject_id = 333)

Answer 4

以下显示满意给定条件的所有独特学生。

SELECT Distinct stud_id
FROM tution
WHERE subject_id=111
AND 
stud_id NOT IN (SELECT stud_id FROM tution WHERE subject_id= 333)

检索满足条件且不满足其他条件的记录

4 个答案: