Question

嗨，这是我在mysql中使用的代码，它的工作正常。有没有办法为GRP声明一个变量并在代码中调用它。所以我可以再次使用代码，如果我必须在grp和任何其他名称之外的其他列上进行数学运算，因为名称一直在变化

     SELECT GRP,
     @_11:=power(GRP,0.1)+0.1*@_11 AS GRP_11 ,
     @_12:=power(GRP,0.2)+0.1*@_12 AS GRP_12 ,
     @_13:=power(GRP,0.3)+0.1*@_13 AS GRP_13 ,
     @_14:=power(GRP,0.4)+0.1*@_14 AS GRP_14 ,
     @_15:=power(GRP,0.5)+0.1*@_15 AS GRP_15 ,
     @_16:=power(GRP,0.6)+0.1*@_16 AS GRP_16 ,
     @_17:=power(GRP,0.7)+0.1*@_17 AS San_Orange_CS_GRP_17 ,
     @_18:=power(GRP,0.8)+0.1*@_18 AS GRP_18 ,
     @_19:=power(GRP,0.9)+0.1*@_19 AS GRP_19 ,
     from DUMMY JOIN (SELECT @_11:=0,@_12:=0,@_13:=0,@_14:=0,@_15:=0,@_16:=0,
     @_17:=0,@_18:=0,@_19:=0) t;

提前致谢...

Answer 1

您可以使用内联变量。

示例：

select @grp:=GRP as grp, @_11:=power( @grp,0.1)+0.1*@_11 AS GRP_11, ...

更改您的查询，如下所示：

SELECT 
     @grp := GRP as grp,
     @_11 := power( @grp, 0.1 ) + 0.1 * @_11 AS GRP_11 ,
     @_12 := power( @grp, 0.2 ) + 0.1 * @_12 AS GRP_12 ,
     @_13 := power( @grp, 0.3 ) + 0.1 * @_13 AS GRP_13 ,
     @_14 := power( @grp, 0.4 ) + 0.1 * @_14 AS GRP_14 ,
     @_15 := power( @grp, 0.5 ) + 0.1 * @_15 AS GRP_15 ,
     @_16 := power( @grp, 0.6 ) + 0.1 * @_16 AS GRP_16 ,
     @_17 := power( @grp, 0.7 ) + 0.1 * @_17 AS San_Orange_CS_GRP_17 ,
     @_18 := power( @grp, 0.8 ) + 0.1 * @_18 AS GRP_18 ,
     @_19 := power( @grp, 0.9 ) + 0.1 * @_19 AS GRP_19 ,
FROM DUMMY
     JOIN ( 
            SELECT @_11:=0, @_12:=0, @_13:=0, @_14:=0, @_15:=0, 
                   @_16:=0, @_17:=0, @_18:=0, @_19:=0 
          ) t;

存储过程使用参数调用特定列

1 个答案: