Question

我有一个字符串，我将其更改为十六进制值，所以我想将它们存储在字节数组中，但它给出了“输入字符串格式不正确”的错误。这是我的代码：

        byte[] PlainText = new byte[16];
        byte[] MasterKey = new byte[16];
        string input = "Hello";
        char[] values = input.ToCharArray();
        int i =0;
        foreach (char letter in values)
        {
            int value = Convert.ToInt32(letter);
            string hexout = String.Format("{0:X}", value);
            PlainText[i++] = Convert.ToByte(hexout);
        }

Answer 1

更改初始代码

    byte[] PlainText = new byte[16];
    byte[] MasterKey = new byte[16];
    string input = "Hello";
    char[] values = input.ToCharArray();
    int i =0;
     string hexout=string.empty;
    foreach (char letter in values)
    {
        int value = Convert.ToInt32(letter);
        hexout+= String.Format("{0:X}", value);

    }
    plaintext=StringToByteArray(hexout);

用于将十六进制转换为字节数组

          public static byte[] StringToByteArray(String hex)
         {
      int NumberChars = hex.Length;
      byte[] bytes = new byte[NumberChars / 2];
       for (int i = 0; i < NumberChars; i += 2)
       bytes[i / 2] = Convert.ToByte(hex.Substring(i, 2), 16);
       return bytes;
      }

或

用于解析长字符串

   public static byte[] StringToByteArray(String hex)
 {
int NumberChars = hex.Length/2;
 byte[] bytes = new byte[NumberChars];
 using (var sr = new StringReader(hex))
{
for (int i = 0; i < NumberChars; i++)
  bytes[i] = 
    Convert.ToByte(new string(new char[2]{(char)sr.Read(), (char)sr.Read()}), 16);
 }
 return bytes;
}

Answer 2

var bytes=System.Text.Encoding.UTF8.GetBytes(yourString);

加密，字符串到字节转换

2 个答案: