Question

我正在复制NodeJS中的EasyNetQ功能（这样Node应用程序就可以通过支持EasyNetQ的.NET应用程序与Rabbit通信）。我已经复制了EasyNetQ的发布/订阅和EasyNetQ的发送/接收，但我在使用EasyNetQ的请求/响应方面遇到了一些困难。

这是我当前的节点代码：

var rqrxID = uuid.v4(); //a GUID
var responseQueue = 'easynetq.response.' + rqrxID;

Q(Play.AMQ.ConfirmChannel.assertQueue(responseQueue, { durable: false, exclusive: true, autoDelete: true }))
.then((okQueueReply) =>
    Play.AMQ.ConfirmChannel.consume(responseQueue, (msg) => {
        //do something here...
        Play.AMQ.ConfirmChannel.ack(msg);
    })
)
.then((okSubscribeReply) => {
    Q(Play.AMQ.ConfirmChannel.assertExchange('easy_net_q_rpc', 'direct', { durable: true, autoDelete: false }))
    .then((okExchangeReply) =>
        Play.AMQ.ConfirmChannel.publish(
            global.AppConfig.amq.rpc.exchange,
            dto.AsyncProcessorCommand.Type,
            Play.ToBuffer(command),
            { type: command.GetType() },
            (err, ok): void => {
                if (err !== null) {
                    console.warn('Message nacked!');
                    responseDeferred.reject(err);
                }
            }
        )
    )
})
.catch((failReason) => {
    console.error(util.format('Error creating response queue: %s', failReason));
    return null;
});

请注意，发布有效，并由.NET代码接收。该代码然后发送响应，问题是没有收到响应。这是.NET代码：

Bus.Respond<AsyncProcessorCommand, AsyncProcessorCommandResponse>(
    request =>
    {
        Console.WriteLine("Got request: '{0}'", request);
        return new AsyncProcessorCommandResponse()
        {
            ID = Guid.NewGuid(),
            ResponseType = "ENQResp"
        };
    });

我确定我错过了什么，但不确定是什么。谁可以帮忙？

更新我已经解决了至少部分问题。获取responseQueue的值并将其设置为发布选项“replyTo”将响应挂起 - 很好。现在我只需弄清楚如何在每次 OR 时都不创建新队列，让响应队列消失......

更新最终 因此，使用我拥有的频道设置并保存cinsumerTag（实际上，指定它）允许我取消消费者并自动删除队列。

Answer 1

从上面的评论中回答这个问题。

这有两件事。首先，从上面的代码中，创建您的响应队列，以便自动删除（当使用者计数降至0时）：

channel.assertQueue(responseQueue, { durable: false, exclusive: true, autoDelete: true }))

然后创建/发布到“服务器”正在侦听的队列 - 确保为刚刚创建的响应队列设置“replyTo”（类型块是另一个需要ENQ的代码）：

{ type: command.GetType(), replyTo: responseQueue }

因此执行此模式的整个（当前是“播放”代码的混乱）方法如下所示：

private static Request(command: dto.AsyncProcessorCommand): Q.Promise<dto.interfaces.IAsyncProcessorCommandResponse> {
    var responseDeferred = Q.defer<dto.interfaces.IAsyncProcessorCommandResponse>();

    var consumerTag = uuid.v4();
    var rqrxID = uuid.v4();
    var responseQueue = 'easynetq.response.' + rqrxID;

    var handleResponse = (msg: any): void => {
        var respType = null;
        switch(command.Action) {
            default:
                respType = 'testResp';
        }

        //just sending *something* back, should come from 'msg'
        responseDeferred.resolve(new dto.AsyncProcessorCommandResponse(respType, { xxx: 'yyy', abc: '123' }));
    }

    Q(Play.AMQ.ConfirmChannel.assertQueue(responseQueue, { durable: false, exclusive: true, autoDelete: true }))
        .then((okQueueReply) =>
            Play.AMQ.ConfirmChannel.consume(responseQueue, (msg) => {
                handleResponse(msg);
                Play.AMQ.ConfirmChannel.ack(msg);
                Play.AMQ.ConfirmChannel.cancel(consumerTag);
            },
            { consumerTag: consumerTag })
        )
        .then((okSubscribeReply) => {
            Q(Play.AMQ.ConfirmChannel.assertExchange('easy_net_q_rpc', 'direct', { durable: true, autoDelete: false }))
            .then((okExchangeReply) =>
                Play.AMQ.ConfirmChannel.publish(
                    'easy_net_q_rpc',
                    dto.AsyncProcessorCommand.Type,
                    Play.ToBuffer(command),
                    { type: command.GetType(), replyTo: responseQueue },
                    (err, ok): void => {
                        if (err !== null) {
                            console.warn('Message nacked!');
                            responseDeferred.reject(err);
                        }
                    }
                )
            )
        })
        .catch((failReason) => {
            console.error(util.format('Error creating response queue: %s', failReason));
            return null;
        });

    return responseDeferred.promise
}

使用nodeJS中的amqplib复制EasyNetQ请求/响应

1 个答案: