Question

因此，我访问数据库以检索员工ID列表，然后获取该员工ID数组，以针对数据库上的另一个表运行查询，该表根据员工ID获取此人的所有信息，但我＆＃39 ; m只获取语句中的最后一个值，但我需要获取并循环所有这些值。任何人都可以看到我的错误吗？

public function manager_list()
{
    $results = array();
    $managers = $this->db->query('select `employee_id` from `managers`');

    foreach($managers->result() as $row)
    {
        $employee_id = $row->employee_id;
    }

        $query = $this->db->query('select `employee_id`, `ssn`, `first_name`, `last_name`, `department`, `title`, `status` from `employees` where `employee_id` = "'.$employee_id.'"');

        foreach ($query->result() as $row){
            $results[] = array(
            'employee_id' => $row->employee_id,
            'ssn' => $row->ssn,
            'first_name' => $row->first_name,
            'last_name' =>$row->last_name,
            'department' =>$row->department,
            'title' =>$row->title,
            'status' =>$row->status,
        );
        }
    return $results; 
}

这是使用代码点火器框架。

Answer 1

~~如果你在一个查询中做到这一点，你可以缩短它，但是因为你说你必须有两个，这里是你的第二个查询的简短版本，不需要foreach循环：~~

<击>
$query = $this->db->query(' select `employee_id`, `ssn`, `first_name`, `last_name`, `department`, `title`, `status` from `employees` where `employee_id` = "'.$employee_id.'"'); return $query->result_array();

使用Active Records：

return $this->db ->select('`employee_id`, `ssn`, `first_name`, `last_name`, `department`, `title`, `status`') ->where(array('employee_id' => $employee_id)) ->get('employees') ->result_array();

<击> 更新

以下是JOIN的简短版本（替换整个代码）：

public function manager_list() { return $this->db ->select('e.employee_id, e.ssn, e.first_name, e.last_name, e.department, e.title, e.status') ->join('managers AS m', 'e.employee_id = m.employee_id') ->where(array('e.employee_id' => $employee_id)) ->get('employees AS e') ->result_array(); }

Answer 2

使用JOIN执行一个查询并执行一个循环 -

public function manager_list()
{
    $results = array();
    $managers = $this->db->query('SELECT `m`.`employee_id`, `e`.`ssn`, `e`.`first_name`, `e`.`last_name`, `e`.`department`, `e`.`title`, `e`.`status` FROM `managers` AS `m` JOIN `employees` AS `e` ON `m`.`employee_id` = `e`.`employee_id`');

    foreach ($managers->result() as $row){
        $results[] = array(
            'employee_id' => $row->employee_id,
            'ssn' => $row->ssn,
            'first_name' => $row->first_name,
            'last_name' =>$row->last_name,
            'department' =>$row->department,
            'title' =>$row->title,
            'status' =>$row->status,
        );
    }
    return $results;
}

没有正确循环

2 个答案: