Question

我正在使用此查询，结果如下：

SELECT     
  t.TestId,
  t.Days,
  t.FullName  
  [Date] = Convert(date,DATEADD(dd, 0, DATEDIFF(dd, 0, t.CheckIn))),
  CheckIn = CONVERT(CHAR(5), t.CheckIn, 108),
  CheckOut = CONVERT(CHAR(5), t.CheckOut, 108),
  [Hours] = CAST(DATEDIFF(MINUTE, t.CheckIn, t.CheckOut) / 60. AS DECIMAL(10,2))
FROM (
  SELECT 
    FullName = Users.FullName,
    TestId = t.TestId,
    Days = t.Days,
    t.UserId_Fk,
    CheckIn = t.CheckInTime,
    CheckOut = r.CheckInTime,
    RowNum = ROW_NUMBER() OVER (PARTITION BY t.UserId_Fk, r.CheckInTime ORDER BY 1/0)
FROM UserTime t 
INNER JOIN Users
ON t.UserId_Fk=Users.UserId
    OUTER APPLY (
      SELECT TOP 1 *
      FROM UserTime t2
      WHERE 
        t2.CheckInTime > t.CheckInTime
        AND DATEADD(dd, 0, DATEDIFF(dd, 0, t.CheckInTime)) = DATEADD(dd, 0, DATEDIFF(dd, 0, t2.CheckInTime))
        AND t2.LoginStatus = 'O'
      ORDER BY t2.CheckInTime
) r
WHERE t.LoginStatus = 'I' 
) t
WHERE t.RowNum = 1

结果：

TestId Days   FullName      Date   CheckIn CheckOut  Hours
11  Wednesday   Antonio 2014-05-14  10:19   10:20   0.02
13  Wednesday   Antonio 2014-05-14  10:19   10:20   0.02
14  Wednesday    Tim    2014-05-14  10:20   10:21   0.02

表格结构：

表用户时间：

TestId   int(pk)    
UserId_Fk    int    
Days     nvarchar(50)
Date         date
CheckInTime  datetime
LoginStatus  char(1)

表用户：

UserId    int(Pk)   
FullName  varchar(50)

我想要一个名为 TotalHours 的列，其中添加了“小时列”的所有字段并显示该值。

有点像这样：

TestId Days     FullName   Date   CheckIn CheckOut Hours  TotalHours
 11 Wednesday   Antonio 2014-05-14  10:19   10:20   0.02    0.04
 11 Wednesday   Antonio 2014-05-14  10:19   10:20   0.02
 13 Wednesday    Tim    2014-05-14  10:20   10:21   0.02

Answer 1

您应该在左侧查询中有两个查询总和小时数，在右侧选择所需的列然后加入查询。

 select * from
   (SELECT testid,sum(Hours) as total from(
       SELECT     
       t.TestId,
       t.FullName  ,
       [Hours] = CAST(DATEDIFF(MINUTE, t.CheckIn, t.CheckOut) / 60. AS DECIMAL(10,2))

      FROM (
            SELECT 
            FullName = Users.FullName,
            TestId = t.TestId,
            Days = t.Days,
            t.UserId_Fk,
            CheckIn = t.CheckInTime,
            CheckOut = r.CheckInTime,
            RowNum = ROW_NUMBER() OVER (PARTITION BY t.UserId_Fk, r.CheckInTime ORDER  BY 1/0)
            FROM UserTime t 
            INNER JOIN Users
            ON t.UserId_Fk=Users.UserId
            OUTER APPLY (
            SELECT TOP 1 *
            FROM UserTime t2
            WHERE 
            t2.CheckInTime > t.CheckInTime
            AND DATEADD(dd, 0, DATEDIFF(dd, 0, t.CheckInTime)) = DATEADD(dd, 0, DATEDIFF(dd, 0, t2.CheckInTime))
       AND t2.LoginStatus = 'O'
  ORDER BY t2.CheckInTime
  ) r
   WHERE t.LoginStatus = 'I' 
  ) t
    WHERE t.RowNum = 1
  )s
  group by s.FullName,testid)O


  INNER JOIN 

  (
   SELECT     
   t.TestId,
   t.Days,
   t.FullName  ,
   [Date] = Convert(date,DATEADD(dd, 0, DATEDIFF(dd, 0, t.CheckIn))),
   CheckIn = CONVERT(CHAR(5), t.CheckIn, 108),
   CheckOut = CONVERT(CHAR(5), t.CheckOut, 108),
   [Hours] = CAST(DATEDIFF(MINUTE, t.CheckIn, t.CheckOut) / 60. AS DECIMAL(10,2))

   FROM (
      SELECT 
      FullName = Users.FullName,
      TestId = t.TestId,
      Days = t.Days,
      t.UserId_Fk,
      CheckIn = t.CheckInTime,
      CheckOut = r.CheckInTime,
      RowNum = ROW_NUMBER() OVER (PARTITION BY t.UserId_Fk, r.CheckInTime ORDER BY 1/0)
      FROM UserTime t 
      INNER JOIN Users
      ON t.UserId_Fk=Users.UserId
      OUTER APPLY (
      SELECT TOP 1 *
  FROM UserTime t2
  WHERE 
    t2.CheckInTime > t.CheckInTime
    AND DATEADD(dd, 0, DATEDIFF(dd, 0, t.CheckInTime)) = DATEADD(dd, 0, DATEDIFF(dd, 0, t2.CheckInTime))
    AND t2.LoginStatus = 'O'
  ORDER BY t2.CheckInTime
 ) r
WHERE t.LoginStatus = 'I' 
 ) t
WHERE t.RowNum = 1
)I
on i.testid=o.testid

添加列的所有行并存储在另一列中

1 个答案: