Question

抓住这个，我有一个表格显示表格中的所有行，整个表格将在表格提交上更新。上下文是这是网站导航。

错误：致命错误：带有消息'SQLSTATE [42000]的未捕获异常'PDOException'：语法错误或访问冲突：1064 SQL语法中有错误;查看与您的MySQL服务器版本相对应的手册，以便在'order ='附近使用正确的语法1'WHERE ID ='1'在1号行的'LIMIT 1'（路径）堆栈跟踪：＃0（路径）：PDOStatement - ＆gt;在第65行（路径）中抛出执行（数组）＃1 {main}

表格：

<form action="<?=$PHP_SELF?>" method="POST">
    <?php 
    $navstmt = $dbh->prepare("SELECT * 
    FROM `navlinks` 
    ORDER BY `order` ASC 
    LIMIT 0 , 30 ");

    $navstmt->execute();

    $result = $navstmt->fetchAll();
    echo "<table width='500px'><tr><td><b>ID</b></td><td><b>Display Title</b></td><td>    <b>Page Name (URL)</b></td><td><b>Order</b></td><td><b>Delete</b></td></tr>";

foreach($result as $row)
    {
    echo '<tr><td><input type="text" name="ID[]" size="4" value="'.$row['ID'] . '"></td><td><input type="text" name="title[]" value="'.$row['title'] . '"></td><td><input type="text" name="url[]" value="'.$row['url'] . '"></td><td><input type="text" name="order[]" size="4" value="'.$row['order'] . '"><td><a href="#"><img src="img/cancel.gif" border="0"></a></td></tr>';
    }
echo '</table>';
?>
<p><input type="submit" name="button" value="Save Changes"></p>

保存到数据库：

<?php
if($_POST['title']){

$size = count($_POST['title']);
$size = count($_POST['url']);
$size = count($_POST['order']);

$i = 0;
while ($i < $size) {

$title = $_POST['title'][$i];
$url = $_POST['url'][$i];
$id = $_POST['ID'][$i];
$order = $_POST['order'][$i];

$sql = "UPDATE navlinks SET title = :title, url = :url, order = :order WHERE ID = :id LIMIT 1";
$q = $dbh->prepare($sql); 
$q->execute(array(':title' => $title, ':url' => $url, ':order' => $order, ':id' => $id));

echo '<div class="alert alert-success"><b>All done!</b> The navigation has been  updated.</div>';
++$i; 

}
}
?>

我确信这可能是非常明显的，但任何帮助都会非常感激！

表观SQL语法错误，使用PHP（PDO）从表单更新多行

0 个答案: